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3 years ago

Find the roots/zeroes of the following polynomial x^2−19=6

Mathematics

2 answers:

zubka84 [21]3 years ago

8 0

Answer:

x=5 and x=-5

Step-by-step explanation:

1. first you would subtract 6 from both sides to set the equation = to zero.

2. The equation would then be x^2-25=0.

3. that is a difference of two squares polynomial. So when you factor it, it is (x+5)(x-5)=0

4. by the zero product property, the roots are 5 and -5.

wel3 years ago

6 0

Your answer is x = 5, -5

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Create a matrix that is equal to F+G. The first matrix below is named F and the second matrix below is named G. Name the new mat

likoan [24]

F+G:

$F+G=\begin{bmatrix}{-1.8} & {-8.6} & {} \\ {2.85} & {-1.4} & {} \\ {-1.8} & {5.1} & {}\end{bmatrix}+\begin{bmatrix}{1.32} & {-1.9} & {} \\ {2.25} & {0.0} & {} \\ {-6.2} & {1.4} & {}\end{bmatrix}$

Then, add the elements that occupy the same position:

$H=\begin{bmatrix}{-1.8+1.32} & {-8.6+(-1.9)} & {} \\ {2.85+2.25} & {-1.4+0.0} & {} \\ {-1.8+(-6.2)} & {5.1+1.4} & {}\end{bmatrix}$

Solve

$H=\begin{bmatrix}{-0.48} & {-10.5} & {} \\ {5.1} & {-1.4} & {} \\ {-8} & {6.5} & {}\end{bmatrix}$

So, we find the element at address h31:

$H=\begin{bmatrix}{h11} & {h12} & {} \\ {h21} & {h22} & {} \\ {h31} & {h32} & {}\end{bmatrix}$

In this case, position h31 is - 8.0

8 0

1 year ago

f the pattern in the table is extended to represent more equivalent ratios for 2:6, which pair of numbers would be in the column

olasank [31]

The pair of numbers that would be in the columns, considering the proportional relationship, is given as follows:

20 would be in the column for 2, and 60 would be in the column for 6.

<h3>What is a proportional relationship?</h3>

A proportional relationship is a special linear function, with intercept having a value of zero, in which the output variable is obtained with the multiplication of the input variable and the constant of proportionality k, as shown as follows:

y = kx

The table is extended to represent more equivalent ratios for 2:6, hence the constant of the relationship is given as follows:

k = 6/2 = 3.

Hence the equation is:

y = 3x.

The values given by each column are given as follows:

Column 2: values of x.

Column 6: values of y.

When x = 20, the numeric value of the relationship is of:

y = 3 x 20 = 60.

Hence the first option is correct.

More can be learned about proportional relationships at brainly.com/question/10424180

#SPJ1

3 0

1 year ago

Which of these strategies would eliminate a variable in the system of equations ?

Mrrafil [7]

Answer:

Step-by-step explanation:

I believe the answer is B because if we multiply the top equation by 6, we get 48x + 30y = -42, and if we multiply the bottom equation by -5, we get

35x - 30y = 20. So now, if we add it all together, then the positive 30y and negative 30y cancel out aka it equals 0, and thus the variable y is gone, satisfying the requirement that the problem asks for ("Which of these strategies would eliminate a variable...").

I hope this helped, and if it's correct, I'd appreciate if you marked my answer as Brainliest :)

7 0

4 years ago

Can anyone solve it plzzzz

Vedmedyk [2.9K]

Answer:

1.A matrix is a rectangular array of numbers, symbols, or expressions, arranged in rows and columns.

Solution given:

We have

Sin² $\theta$ -Cos ² $\theta$ =1

Sin² $\theta$ =1+Cos² $\theta$

Sin $\theta$ = $\sqrt{1-Cos²\theta}$

4Tan² $\theta$ +4Cot² $\theta$ -3Tan² $\theta$ -3Cot² $\theta$

4Tan² $\theta$ -3Tan² $\theta$ +4Cot² $\theta$ -3Cot² $\theta$

Tan² $\theta$ -Cot² $\theta$

7 0

3 years ago

In ΔABC, AD and BE are the angle bisectors of ∠A and ∠B and DE║ AB. Find the measures of the angles of ΔABC, if m∠ADE: m∠ADB = 2

drek231 [11]

Answer: ∠A=48°,∠B=48°,∠C=84°.

Step by-step explanation:

Given: AD and BE are the angle bisectors of ∠A and ∠B

i.e ∠6=∠7 ( ∵ Angles formed after AD bisected ∠A)

∠4=∠5 ( ∵ Angles formed after BE bisected ∠B)

Also, DE║AB

⇒ ∠2=∠7 (∵ Alternate interior angles)

∠3=∠6 (∵ Alternate interior angles)

And ∠ADE : ∠ADB =∠2:∠3= 2:9 =2x : 9x ..(1)

To Find: ∠A,∠B,∠C.

Solution: ∠2=∠7 (∵ Given) ...(2)

∠2=∠4 (∵ angles on the same segment) ...(3)

∠4=∠5 =∠B/2 (∵ Given) ...(4)

∴ In Δ ABD

∠3+∠4+∠5+∠7 = 180 (∵ Sum of interior angles of a triangle)

From equation 2,3,4,5, Put values

9x+2x+2x+2x =180°

⇒15x = 180°

⇒x=12°

Putting values in equation (4) ⇒ ∠ B =2*(2*12) = 48°

Also, <u>∠B=∠A=48°</u>

Now,in Δ ABC

∠C+∠B+∠A= 180°

⇒48°+48°+∠C= 180°

<u><em>⇒∠C=84°</em></u>

6 0

4 years ago