Just need some help please

Mathematics

2 answers:

zaharov [31]3 years ago

6 0

I’m pretty sure you cut out an answer choice because none of those listed are correct so It should be D if D is “y=4/5x-2”. It’s NOT B because the line on the graph is positive and not negative.

Vlad1618 [11]3 years ago

4 0

Answer:

It is y = -4/5x - 2 because you go left 4 and down 5 which makes both negative. And of course it is minus two.

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Answer:

40%

Step-by-step explanation:

First off, 1/5 is equal to 20%. If you're diving something into 5ths, you can do 100 / 5, which is 20. So you know that Raul scored at least 20% of the points. His friend Jake ALSO scores 20% of the teams points, making 20 + 20 = 40%. Therefore, 40% of the teams points were scored by Raul and Jake.

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2 years ago

A particular variety of watermelon weighs on average 20.4 pounds with a standard deviation of 1.23 pounds. Consider the sample m

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Answer:

a) The expected value of the sample mean weight is 20.4 pounds.

b)The standard deviation of the sample mean weight is 0.123.

c) There is a 14.46% probability the sample mean weight will be less than 20.27.

d) This value is $c = 20.6153$ .

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

A particular variety of watermelon weighs on average 20.4 pounds with a standard deviation of 1.23 pounds. This means that $\mu = 20.4, \sigma = 1.23$