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3 years ago

Suzie has 55 pairs of shoes which is 33 less than twice the amount of shoes Jamie has. how many pairs of shoes does Jamie have

Mathematics

1 answer:

tankabanditka [31]3 years ago

4 0

Answer:

Jamie has 44 pairs of shoes

Step-by-step explanation:

Let

Jamie= x pairs of shoes

Suzie= 33 less than twice the amount of shoes Jamie has

2x - 33 = 55

Solve:

2x - 33 = 55

Collect like terms

2x = 55 + 33

2x = 88

Divide both sides by 2

2x / 2 = 88 / 2

x = 44

Jamie = x = 44 pairs of shoes

Therefore, Jamie has 44 pairs of shoes

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babymother [125]

Answer:

6x to find x on it's own you need to divide by the number infront,

Step-by-step explanation:

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4 years ago

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The local bike shop sells a bike and accessories package for $320 if the bike is worth 7 times more than the accessories,how muc

sdas [7]

So, bike=b and accessories=a.

b+a=320

Since the bike is worth 7 times more than the accessories, the b would turn into 7a (because 7 times the cost of accessories is the cost of the bike).

The equation would now turn into 7a+a=320.

Solve for a.

7a+a=320
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Now that you know the cost of the accessories, you multiply that 40
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3 years ago

A dozen apples cost$4.92 for a dozen apples is a ratio of what per Apple

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Answer:

12 : 4.92

Step-by-step explanation:

a= apples

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12 : 4.92

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3 years ago

Use the Taylor series you just found for sinc(x) to find the Taylor series for f(x) = (integral from 0 to x) of sinc(t)dt based

Marina CMI [18]

In this question (brainly.com/question/12792658) I derived the Taylor series for $\mathrm{sinc}\,x$ about $x=0$ :

$\mathrm{sinc}\,x=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}$

Then the Taylor series for

$f(x)=\displaystyle\int_0^x\mathrm{sinc}\,t\,\mathrm dt$

is obtained by integrating the series above:

$f(x)=\displaystyle\int\sum_{n=0}^\infty\frac{(-1)^nx^{2n}}{(2n+1)!}\,\mathrm dx=C+\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

We have $f(0)=0$ , so $C=0$ and so

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}$

which converges by the ratio test if the following limit is less than 1:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(-1)^{n+1}x^{2n+3}}{(2n+3)^2(2n+2)!}}{\frac{(-1)^nx^{2n+1}}{(2n+1)^2(2n)!}}\right|=|x^2|\lim_{n\to\infty}\frac{(2n+1)^2(2n)!}{(2n+3)^2(2n+2)!}$

Like in the linked problem, the limit is 0 so the series for $f(x)$ converges everywhere.

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3 years ago

An architect wants to draw a rectangle with a diagonal of 13 centimeters. The length of the rectangle is to be 3 centimeters mor

butalik [34]

Answer:

The rectangle is 3.2 cm by 12.6 cm

Step-by-step explanation:

See attached image for a diagram.

Choose w to represent the width because the length is described by referring to the width: it's 3 more than (add 3) triple (multiplied by 3) the width.

Length = 3w + 3

The diagonal forms two right triangles, each with leg = w, other leg = 3w + 3, hypotenuse = 13.

The Pythagorean Theorem says $(\text{leg})^2+(\text{leg})^2=(\text{hypotenuse})^2$ so

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Now solve using the Quadratic Formula with $a=5,\,b=9,\,c=-80$ .

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The negative root makes no sense as a distance, so the width of the rectangle is 3.2 cm. The length is 3(3.2) + 3 = 12.6 cm.

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3 years ago