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yKpoI14uk [10]
2 years ago
6

50 POINTS !! PLEASE HELP !! ILL GIVE BRAINLIEST TO THE RIGHT ANSWERS.

Mathematics
2 answers:
DiKsa [7]2 years ago
7 0

Answer:

a = 56.

Step-by-step explanation:

Step 1: <u>Mathematics: Define and explain.</u>

In order to find the missing side of a right triangle, you must use the Pythagorean Theorem.

This theorem states that the legs of a triangle, squared, must equal the hypotenuse, squared.

The legs of the triangle are the sides that form the right angle. Which in this case, are 33 m and 'a.'

The hypotenuse is the longest side, which in this case, is 65 m.

Step 2: <u>Mathematics: Solve.</u>

theorem-a^2+b^2=c^2

legs-a,b

hypotenuse-c

Now, I will solve for one of the legs.

a^2+33^2=65^2

a^2+1089=4225

4225-1089=3136

a^2=3136\\

a=56

Step 3: <u>Mathematics: Conclude</u>

Therefore, the missing side is 56 meters.

Musya8 [376]2 years ago
5 0

Answer:

The length of the missing leg is 56 meters.

Step-by-step explanation:

Use the Pythagorean theorem to figure out the leg of the missing leg.

Formula: a^2+b^2=c^2, given a=leg, b=leg, and c=hypotenuse

The hypotenuse is 65 meters, and one of the legs is 33 meters, so plug it into the formula and solve for a.

a^2+33^2=65^2

a^2+1089=4225

a^2=3136

Take the square root of both sides, and you get 56 meters.

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velikii [3]

Answer:

(0,34)

Step-by-step explanation:

For each rise of 14 in the x direction, this graph rises by -8 in the y direction. This means that, when x is 0, and the graph intersects the y axis, the y value will be 50-8-8=34. Therefore, the y intercept of this line is (0,34). Hope this helps!

7 0
3 years ago
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A closed cylindrical tank of radius 1.50m and height 300cm, is made from a metal sheet. How much sheet is required?
Anika [276]

Answer: 13.5π≈42.41

Step-by-step explanation:

Basically it is asking for the circumference of this cylinder.

#1 Find the circumference of the circle base

Formula to use: 2πr

2πr=2π(1.5)=3π

---------------------------

#2 Find the area of the circle base

Formula to use: πr²

πr²=π(1.5)²=2.25π

--------------------------

#3 Find the area of body of the cylinder

Formula to use: lw

300cm=3m

l (length)= 3π (since the body of the cylinder the basing on the circumference of the circle base)

w (width)= 3

lw=3π×3m=9π

----------------------------

#4 Add all of them together

There are 2 base and one body

2.25π×2+9π=13.5π

4 0
3 years ago
If a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then which statement would be true
aleksley [76]

- I think it's possibly this "The figure must be a square because the diagonals of a square bisect the right angles." but there's also "The figure must be a rhombus because it has exactly 2 pairs of congruent angles." buuut since the first one seems more better i'm assuming then that's probably the right answer.

5 0
3 years ago
What is the area of the trapezoid shown below?​
Olin [163]

Answer:

78 sqr units

Step-by-step explanation:

Use the Pythagorean Theorem to help find the base opposite the two.

The base of the second parallel line is sqrt(  (15^2) - (12^2)  ) = sqrt(81) = 9

The second base = 9 + 2 = 11

Area = (b1 + b2)*h/2

h = 12

b1 = 2

b2 = 11

h = 12

Area = (11 + 2)*12/2

Area = 13 * 12/2

Area = 78 square units

7 0
3 years ago
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It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp​
Semmy [17]

Answer:

\frac{1}{5}

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} = a^{(m+n)}, \frac{a^{m} }{a^{n} } = a^{(m-n)}, (a^m)^{n} = a^{mn}

Simplifying the product of the first 2 terms

\frac{a^{p^2+pq} }{a^{pq+q^2} } × \frac{a^{q^2+qr} }{a^{qr+r^2} }

= a^{p^2-q^2} × a^{q^2-r^2}

= a^{p^2-r^2}

Simplifying the third term

5((a^p+r)^{p-r}

= 5a^{(p+r)(p-r)} = 5a^{(p^2-r^2)}

Performing the division, that is

\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} } ← cancel a^{(p^2-r^2)} on numerator/ denominator leaves

= \frac{1}{5}

4 0
2 years ago
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