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2 years ago

Choose the equation that represents the line that passes through the point (-1, 6) and has a slope of (-3).

Mathematics

1 answer:

expeople1 [14]2 years ago

8 0

It’s c bro yes it is

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What is the answer and how did you get it

Otrada [13]

Answer:

You didn't include a picture!

Step-by-step explanation:

Fun fact ; More twins are born now then they ever were before!

4 0

2 years ago

In the name katherine, fine the ratio of consonants to vowels. PLEASE HELP 100 POINTS WORTH!!!!!!!

Andrei [34K]

Answer:

5:4

Step-by-step explanation:

separate katherine into consonants:

kthrn

and vowels:

aeie

there are 5 consonants and 4 vowels, so the ratio is 5:4.

5 0

3 years ago

Read 2 more answers

The sum of three consecutive odd integers is 195. Find the three integers.

Anettt [7]

Good afternoon,

x= first odd integer
x+2 = second odd integer
x+4= third intenger

The sum of the trhree integer is 195, so:

x + (x+2) + (x+4) = 195
3x = 195 - 4 - 2
3x=189
x= 63

Then the Answer is: 63, 65 and 67

8 0

3 years ago

Read 2 more answers

Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of

Alexxx [7]

Answer:

a) 0.018

b) 0

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)$

$= 1 - P(z \leq 2.1)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%$

0.018 is the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected men, these men have a mean hip breadth greater than 16.5 in)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

P(x > 16.5)

$P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)$

$= 1 - P(z \leq 23.29)$

Calculation the value from standard normal z table, we have,

$P(x > 16.5) = 1 - 1 = 0$

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

4 0

3 years ago

Regroup. Write the missing numbers. 40 tens = ___ hundreds

Genrish500 [490]

Write the missing numbers. 40 tens = ___ hundreds

40 * 10 = 400

so:

40 tens = 4 hundreds

7 0

1 year ago