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Sunny_sXe [5.5K]
3 years ago
14

A package of of 500 sheets of computer paper has dimensions of 8 1/2 x 11x2. How many packages will fit in a box with 17 1/2x12x

10
Mathematics
1 answer:
just olya [345]3 years ago
6 0
Volume of the 1st package : 8.5x11x2 =187 in³

Volume of the 2nd package = 17.5x12x10 = 2,100 in³


Number of packages that fit = V₂/V₁ = 2100/187 = 11.23 Packages
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Drag each condition to the correct location on the table.
Marizza181 [45]

Answer:

Condition A= 320 inches

Condition B= 190 Degrees F

Condition C= 2240 inches

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Condition E= 110 Degrees F 8 inches

Condition F= 180 Degrees F

Step-by-step explanation:

4 inches

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What expression is correct?​
Mazyrski [523]

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Step-by-step explanation:*mine doesn’t have the line and stuff to show u how to explain it*

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Determine the number of solutions the system of 1/3y-5=2x and y=3(2x+5)
lorasvet [3.4K]

Answer:

A. (4,1)

Step-by-step explanation:

2x -5y = 3

x -3y = 1

Change the equation to isolate a variable so you can substitute it in the other one.

x = 1+3y so

2(1+3y) -5y = 3

2 + 6y -5y =3

2 + y = 3

y=1

Back to the easy equation we isolated

x = 1+3(1)

x= 4

(4,1) is a point where x=4 and y=1

hendikeps2 and 22 more users found this answer helpful

THANKS

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Step-by-step explanation:

3 0
3 years ago
Marine scientists categorize signature whistles of bottlenose dolphins by typelong dash—type ​a, type​ b, type​ c, etc. In one s
r-ruslan [8.4K]

Answer:

The 95​% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 185, \pi = \frac{100}{185} = 0.5405

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 - 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.4687

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.5405 + 1.96\sqrt{\frac{0.5405*0.4595}{185}} = 0.6123

The 95​% confidence interval for the true proportion of bottlenose dolphin signature whistles that are type a whistles is (0.4687, 0.6123).

3 0
3 years ago
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