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zaharov [31]
3 years ago
10

My best friend doesn't know the answer i aaint answering it for him help him help this dumbo

Mathematics
1 answer:
ruslelena [56]3 years ago
7 0

Answer:

5 batches

Step-by-step explanation:

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Tennis balls cost 7$ for a can of 3. Steve gives the cashier $40 to buy balls and receives $12 in change. How many tennis balls
Keith_Richards [23]
4 cans. 12 tennis balls.
6 0
3 years ago
Niki makes the same payment every two months to pay off his $61,600 loan. The loan has an interest rate of 9.84%, compounded eve
Alenkasestr [34]
The question is an annuity question with the present value of the annuity given.
The present value of an annuity is given by PV = P(1 - (1 + r/t)^-nt) / (r/t) where PV = $61,600; r = interest rate = 9.84% = 0.0984; t = number of payments in a year = 6; n = number of years = 11 years and P is the periodic payment.
61600 = P(1 - (1 + 0.0984/6)^-(11 x 6)) / (0.0984 / 6)
61600 = P(1 - (1 + 0.0164)^-66) / 0.0164
61600 x 0.0164 = P(1 - (1.0164)^-66)
1010.24 = P(1 - 0.341769) = 0.658231P
P = 1010.24 / 0.658231 = 1534.78
Thus, Niki pays $1,534.78 every two months for eleven years.
The total payment made by Niki = 11 x 6 x 1,534.78 = $101,295.48
Therefore, interest paid by Niki = $101,295.48 - $61,600 = $39,695.48
8 0
3 years ago
Read 2 more answers
Find a point-slope form for the line with slope 1/5<br> and passing through the point (-7,-4).
Basile [38]

Answer:

y + 4 = ⅕(x + 7)  

Step-by-step explanation:

The "point-slope" form of the equation of a straight line is:

y − y₁ = m(x − x₁)

where m is the slope and (x₁, y₁) is a point on the line.

If m = ⅕ and (x₁, y₁) = (-7,  - 4), the point-slope equation is

y + 4 = ⅕(x + 7)

The Figure below shows the graph of your line and a point at (-7, -4).

6 0
3 years ago
Help please <br><br> look at picture <br><br> supplementary angles
8_murik_8 [283]

Answer:

x=16

Step-by-step explanation:

....,...................

5 0
2 years ago
If y=1/2 when x=2, find y when x=3, given that y varies directly with x
Lelu [443]
\bf \qquad \qquad \textit{direct proportional variation}\\\\&#10;\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby &#10;\begin{array}{llll}&#10;k=constant\ of\\&#10;\qquad  variation&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\textit{we also know that }&#10;\begin{cases}&#10;y=\frac{1}{2}\\&#10;x=2&#10;\end{cases}\implies \cfrac{1}{2}=k2\implies \cfrac{1}{4}=k&#10;\\\\\\&#10;\boxed{y=\cfrac{1}{4}x}&#10;\\\\\\&#10;\textit{when x=3, what is \underline{y}?}\qquad y=\cfrac{1}{4}\cdot 3
4 0
3 years ago
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