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vfiekz [6]
3 years ago
14

Please help in confused

Mathematics
2 answers:
Darya [45]3 years ago
8 0

Answer:

the first answer is correct and brainliest plsss (^_^)

Step-by-step explanation:

Yanka [14]3 years ago
7 0
Answer: (-2,-1)

Explanation: When looking at graphs you need to look at the horizontal line / the one thats flat, most graphs are -10 to 10, the point in the middle is 0 if you go right you're going negative, left is positive, so C is 2 times left from the middle point so the first number is (-2,?); now the vertical line is kind of the same, but now going down will be a negative and going up will be a positive, C is going down one. So for C the coordinates are (-2,-1)
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Consider the linear expression and a first step of simplification shown below.
wlad13 [49]

Answer:

Commutative Property

Step-by-step explanation:

From step 1 to step 2, we are changing the order, that means we are using the Commutative Property.  The Commutative Property means to move around, or a+b = b+a


6 0
3 years ago
Factor completely 5x(x + 3) + 6(x + 3). (1 point)
11111nata11111 [884]

Answer:

<h3>The answer is ( 5x + 6 ) ( x + 3 )</h3>

Step-by-step explanation:

5x(x + 3) + 6(x + 3)

The final answer is

( 5x + 6 ) ( x + 3 )

Hope this helps you

7 0
3 years ago
Which of the following doesn't belong?
nignag [31]
<span>36 does not belong in that group because it is the only number that is not a power of 2:

2^2 OR 2 x 2 = 4
2^3 OR 2 x 2 x 2 = 8
2^4 OR 2 x 2 x 2 x 2 = 16
2^5 OR 2 x 2 x 2 x 2 x 2= 32
2^6 OR 2 x 2 x 2 x 2 x 2 x 2= 64</span>
7 0
4 years ago
A B C or D you can only choose one ​
Vlada [557]

Answer: first one

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
5. The volleyball team has a double-header on Friday. The probability that they
Nikolay [14]

Answer: 54.29%

Step-by-step explanation:

Given: The probability that they  will win both games is 38%.

i.e. P( both games will win) =0.38

The probability that they will win just the first game is  70%.

P(first game will win) = 0.70

To find : P(second game will win| first game will win)

Using formula: P(B|A)=\dfrac{P(\text{both A and B})}{P(A)}

So, P(second game will win| first game will win) = \dfrac{\text{ P( both games will win)}}{\text{P(first game will win)}}

=\frac{0.38}{0.70}\approx0.5429=54.29\%

Hence, the required probability = 54.29%

4 0
3 years ago
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