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Nikitich [7]
3 years ago
5

Prano se bhi Pyara answer​

Mathematics
1 answer:
klio [65]3 years ago
7 0
Möchtest du trinken
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Given an initial quantity Q0=150 and a growth rate of 7% per unit time, give a formula for the quantity Q as a function of time
rodikova [14]

Answer:

Step-by-step explanation:

From the given information:

(a)

Since growth quantity is not continuous

Q(t) = 150 (1.07)^t

For t = 10

Q(10) = 150 (1.07)^{10}

\mathbf{Q(10) = 295.073}

(b)

Here, for a continuous growth rate, the growth quantity can be computed in terms of initial quantity and the growth rate.

i.e.

Q(t) = 150 e^{0.07t}

At t = 10 for a continuous growth rate;

Q(10) = 150 e^{0.07  \times 10}

Q(10) = 150 e^{0.7}

\mathbf{Q(10) = 302.063}

8 0
3 years ago
Whoever helps with number 3 gets brainliest answer and 10 points :)
statuscvo [17]
53 is the mean
70 is the range
there is no mode
51 is the median
4 0
3 years ago
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Question<br> What is the factored form of this polynomial?<br> p(x) = x + 7x2 + 4x - 12
Soloha48 [4]

Answer:

^(3)+7x^(2)+4x-12

Step-by-step explanation:

8 0
3 years ago
From a point on a river, two boats are driven in opposite directions, one at 7 miles per hour and the other at 11 miles per hour
Bogdan [553]

Answer:

Both boats will be 54 miles apart after 3 hours.

Step-by-step explanation:

Given that from a point on a river, two boats are driven in opposite directions, one at 7 miles per hour and the other at 11 miles per hour, to determine how many hours they will be 54 miles apart, the following calculation must be performed :

54 / (11 + 7) = X

54/18 = X

3 = X

Therefore, both boats will be 54 miles apart after 3 hours.

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3 years ago
Round 36, 993 to nearest thousands
Natalija [7]
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