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PIT_PIT [208]
2 years ago
12

Brianna has a 50$ online gift certificate from a book store. The cost of each book is $9. There is also a shipping charge of 5$

for her entire order. How many books can Brianna buy without spending more than her gift certificate amount?
Mathematics
2 answers:
ZanzabumX [31]2 years ago
6 0

Answer:

5 books

Step-by-step explanation:

I just went through the nines multiplication table until I got to 9 * 5 which equals 45, and then since it charges $5 for the shipping fee, $45 + $5 = $50 so 5 books would be the amount she can buy

Schach [20]2 years ago
5 0

Answer:

5

Step-by-step explanation:

9x+5=50

9x=45

x=5

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Natalka [10]

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Step-by-step explanation:

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plz some one help/ If the​ x- and​ y-values in a​ one-to-many relation are​ reversed, then in the resulting relation ( ) input o
Reika [66]

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6 0
3 years ago
Olivia has a points card for a movie theater. She receives 25 rewards points just for signing up. She earns 7.5 points for each
andrezito [222]

Answer:

0 visits

Step-by-step explanation:

According to the scenario, calculation of the given data are as follows,

Rewards for signing up = 80 points

Reward per visit = 2.5 points

Total points needed = 105

Let, number of visits = x

So, we can calculate number of visits by using following formula,

80 + (2.5 × X) = 105

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X = 25 ÷ 2.5

X = 10 visits.

Hence, Olivia needs to make 10 visits in order to earn a free movie ticket

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What would you multiply the fraction 12/28 by to make the product equal 1?
Grace [21]

it's 21/21 which would simplify to 1


How I got that answer was by multiplying 3/7 and 7/3 to get 21 both times

8 0
4 years ago
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
bezimeni [28]

Answer:

See explanation and results below.

Step-by-step explanation:

We have the following data:

Age​ (yr) when award was won Frequency 25​-34 31 35​-44 36 45​-54 12 55​-64 4 65​-74 6 75​-84 1 85​-94 2

If we order the data we got the following result. We assume that the midpoint is given by:

Midpoint= \frac{L.Limit +U.Limit}{2}

The Class.Width = U.Limit-L.Limit

And the limits are given by the lower and upper limit.

L.Limit  U.Limit Class W  Midpoint  Frequency   Limits

  25         34     34-25=9     29.5           31           [25-34]                

  35         44      44-35=9     39.5          36           [35-44]

  45         54      54-45=9     49.5           12           [45-54]

  55         64      64-55=9     59.5           4            [55-64]

  65         74       74-65=9     69.5           6            [65-74]

  75          84      84-75=9     79.5            1            [75-84]

  85          94      94-85=9     89.5           2           [85-94]

8 0
3 years ago
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