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Orlov [11]
3 years ago
10

4.1 < 12can someone please help me?​

Mathematics
1 answer:
Sholpan [36]3 years ago
6 0

Answer:

12 is greater

Step-by-step explanation:

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EastWind [94]

Answer:

DE

i think.

hope this helps :)

3 0
3 years ago
I need help with this problem
Dahasolnce [82]

when you got a variable that is x it stays the same it becomes a invisible 1

multiply 12 by 9 the answer is 108

x=108

8 0
3 years ago
Animal populations are not capable of unrestricted growth because of limited habitat and food supplies. Under such conditions th
trasher [3.6K]

Answer:

(a) 100 fishes

(b) t = 10: 483 fishes

    t = 20: 999 fishes

    t = 30: 1168 fishes

(c)

P(\infty) = 1200

Step-by-step explanation:

Given

P(t) =\frac{d}{1+ke^-{ct}}

d = 1200\\k = 11\\c=0.2

Solving (a): Fishes at t = 0

This gives:

P(0) =\frac{1200}{1+11*e^-{0.2*0}}

P(0) =\frac{1200}{1+11*e^-{0}}

P(0) =\frac{1200}{1+11*1}

P(0) =\frac{1200}{1+11}

P(0) =\frac{1200}{12}

P(0) = 100

Solving (a): Fishes at t = 10, 20, 30

t = 10

P(10) =\frac{1200}{1+11*e^-{0.2*10}} =\frac{1200}{1+11*e^-{2}}\\\\P(10) =\frac{1200}{1+11*0.135}=\frac{1200}{2.485}\\\\P(10) =483

t = 20

P(20) =\frac{1200}{1+11*e^-{0.2*20}} =\frac{1200}{1+11*e^-{4}}\\\\P(20) =\frac{1200}{1+11*0.0183}=\frac{1200}{1.2013}\\\\P(20) =999

t = 30

P(30) =\frac{1200}{1+11*e^-{0.2*30}} =\frac{1200}{1+11*e^-{6}}\\\\P(30) =\frac{1200}{1+11*0.00247}=\frac{1200}{1.0273}\\\\P(30) =1168

Solving (c): \lim_{t \to \infty} P(t)

In (b) above.

Notice that as t increases from 10 to 20 to 30, the values of e^{-ct} decreases

This implies that:

{t \to \infty} = {e^{-ct} \to 0}

So:

The value of P(t) for large values is:

P(\infty) = \frac{1200}{1 + 11 * 0}

P(\infty) = \frac{1200}{1 + 0}

P(\infty) = \frac{1200}{1}

P(\infty) = 1200

5 0
3 years ago
I need help fast will give brainliest!!!
givi [52]

Answer:

C and D

Step-by-step explanation:

the answers are C and D.

6 0
3 years ago
Please HElp WAS DUE YESTERDAY this is my last question
Naily [24]

Answer:

Look below

Step-by-step explanation:

To verify that the solution is (3,4) we can plug the numbers back into the equation.

Remember that the solution to a linear equation is represented in the form (x,y). Therefore we plug 3 in for x and 4 in for y.

4=3+1

4=4 Correct!

Now we need to check the second equation

4=-2(3)+10

4=-6+10

4=4 Correct!

Therefore the solution is (3,4)

4 0
3 years ago
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