When (1,2) is substituted into the first equation, the equation is true.
The ordered pair (1,2) is a solution to the system of linear equations.
When (1,2) is substituted into the second equation, the equation is true.
Answer:
wruwgwjwggwwfjjwtjgwjwgjwjyjwgek
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Answer:
= 30,550 rupee owed
Step-by-step explanation:
yr1 = 50000 x 0.10^1 = 5000
5000 - 10000 = 5000 credit from debt.
yr 2 = 50000 x 1.10^2 = 500 debit from debt = 5000-15000= 10,000 credit from debt
yr 3 = 50000 x 1.10^3 = 50 debit from debt
5000 + 500 = 15000 where 50,000 owed initially and yr1 and yr 2 paid in full interest of 5500 and we deduct this from his payment = 25000-5500 =
19500 paid of initial and nothing owed on interest.
50000-19500= 30,500 rupees owed + 50 rupee interest.
= 30,550 rupee owed
Im sorry but i really cant see any of the words or number and ik this
Answer:
I have come to the conclusion that it is A. 112,000
