(a+b)^7= a^7+ 7a^7b+ 21 a^6b²+ 35a^5b³+ 35 a⁴b⁴+ 21 a³b^5 + 7a²b^6 + b^7
(75 * X) - 58 = 283
Not really much to explain here, sorry.
Answer:
The answer should be 64.21 or 64
Step-by-step explanation:
Help this Helped
Answer:
Step-by-step explanation:
y = 3x - 5
6x + 3y = 15
Substitute the first equation into the second
6x + 3(3x - 5) = 15
6x + 9x - 15 = 15
15x = 30
x = 2
Then use the answer in the first equation and solve
y = 3(2) - 5
y = 6 - 5
y = 1
any of the 34 cars can finish first
any of the remaining 33 cars can finish second
any of the remaining 32 cars can finish third
Thus, the top 3 finishes can be done in (34)(33)(32) = 35904 ways
