Answer:
Group B has the higher median by 0.5 inches. The IQR for Group A is smaller. IQR for Group B is 2 inches.
Answer:
5 times as many
<em>BRAINLIEST, please!</em>
Step-by-step explanation:
I'd need more information about how many students there are at one of the schools. For example, if there are 200 students at Park Elementary, then there are 1000 at Lane High School since 200 x 5 = 1000. 1000 - 200 is 800, so there would be 800 more students at Lane High.
Answer:
16.68 cm
Step-by-step explanation:
Given that :
Mean , m = 15
Standard deviation, s = 2
Length of salamander that would Place it at 80% of salamander length :
P(Z ≤ x) = 0.8
Zscore equivalent to 0.8 = 0.842
Using the relation :
Zscore = (x - m) /s
0.842 = (x - 15) / 2
1.684 = x - 15
Add 15 to both sides
1.684 + 15 = x - 15 + 15
16.684 = x
Hence, x = 16.68 cm
Answer:
≈50.6
Step-by-step explanation:
Not sure what precision level this problem is looking for, but for right-skewed distributions, we know that the mean is going to be pulled right and therefore the mean should be larger than the median. To a high confidence level, the mean should fall between 50 and 59, or in the third column.
If a single estimation is wanted, assume the values inside each column are uniformly distributed: