The side lengths of a triangle are 6, 8, and 12. Is this a right triangle?

Mathematics

2 answers:

gizmo_the_mogwai [7]3 years ago

8 0

<h2><u>D.</u></h2><h3>It's incorrect, because 6 squared = 36, 8 squared = 64, add them together and you get 100. 12 squared does NOT equal 100, it equals 144.</h3>

<em>(To find the hypotenuse {longest side of the triangle}, you square the two short sides, add them together, and finally, divide it by the provided number, and see if the number matches the provided number's square.)</em>

<h3>Brainly if correct and Thanks!</h3>

dlinn [17]3 years ago

7 0

Answer:

D) No, because 6²+8²≠12²

Step-by-step explanation:

In order for it to be a right triangle, the sum of the squares of the side lengths must be equal to the square of the hypotenuse.

In this case, 6^2+8^2=36+64=100. Since 100≠144, this means that option D is correct

You might be interested in

Can someone help me with this pls?

madam [21]

Please bare with me bc I’m bad at wording things, change it as you please!

It’s a minimum. I know that the function is a minimum because whenever there is a - in the beginning of the equation it flips your parabola over the x axis and my parabola becomes concave down. When my parabola is concave up I have a minimum, vise versa is a maximum. Because there isn’t a -, my parabola is concave up meaning the function has a minimum

6 0

2 years ago

What time is number 12? Please help

mezya [45]

Answer:

I say its number 2

Step-by-step explanation:

7 0

3 years ago

what is 7 divided by 1/3 in multiplication is it A.1/3 multiplied by 7 =k B. 1/3 multiplied by k=7 or C. 1/3=k multiplied by 7.

NeX [460]

Answer:

B. 1/3 multiplied by k=7

Step-by-step explanation:

7 ÷ ⅓ = k

Multiply both sides by ⅓

7 ÷ ⅓ × ⅓ = k × ⅓

7 = k × ⅓

4 0

3 years ago

For questions 3 – 5, an airplane is heading south at an airspeed of 540 km/hr, but there is a wind blowing from the northeast at

GuDViN [60]

First, let's calculate the horizontal and vertical components of the wind speed (W) and the airplane speed (A), knowing that south is a bearing of 270° and northeast is a bearing of 45°:

$\begin{gathered} W_x=W\cos45°\\ \\ W_x=50\cdot0.707\\ \\ W_x=35.35\\ \\ \\ \\ W_y=W\sin45°\\ \\ W_y=50\cdot0.707\\ \\ W_y=35.35 \end{gathered}$ $\begin{gathered} A_x=A\cos270°\\ \\ A_x=540\cdot0\\ \\ A_x=0\\ \\ \\ \\ A_y=A\sin270°\\ \\ A_y=540\cdot(-1)\\ \\ A_y=-540 \end{gathered}$

Now, let's add the components of the same direction: