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Debora [2.8K]
3 years ago
15

During an experiment, Juan rolled a six-sided number cube 18 times. The number two occurred four times. Juan claimed the experim

ental probability of rolling a two was approximately StartFraction 1 over 9 EndFraction. Which of the following is true about Juan’s claim?
Juan's claim is incorrect. The correct experimental probablilty is StartFraction 2 over 9 EndFraction.
Juan's claim is incorrect. The correct experimental probablilty is One-third.
Juan's claim is incorrect. The correct experimental probablilty is StartFraction 4 over 9 EndFraction.
Juan’s claim is correct.
Mathematics
2 answers:
Maru [420]3 years ago
8 0

Answer:

1) Juans claim is incorrect. The correct experimental probablilty is 2/9

Step-by-step explanation:

stiks02 [169]3 years ago
3 0

Answer:

a

Step-by-step explanation:

Juan's claim is incorrect. The correct experimental probablilty is 2/9

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Plug in the value of x into y = \frac{7x + 1}{3x - 6}

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Answer:

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12b. Subtraction = – y⁵ – 3y³ + 8y + 11

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13b. Subtraction = – x⁴ – 9x³ –6x² + 8x + 3

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15b. Subtraction = m⁵ – m⁴ – m³ – m² – 10

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Step-by-step explanation:

12a. Addition

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+ (4y⁵ + 5y³– 7y – 8)

————————————

= 7y⁵ + 7y³ – 6y – 5

12b. Subtraction

.. 3y⁵ + 2y³ + y + 3

– (4y⁵ + 5y³– 7y – 8)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= – y⁵ – 3y³ + 8y + 11

13a. Addition

.. 2x⁴ – 4x³ – 6x² + 8x + 10

+ (3x⁴ + 5x³ +...................+ 7)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= 5x⁴ + x³ – 6x² + 8x + 17

13b. Subtraction

.. 2x⁴ – 4x³ – 6x² + 8x + 10

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= – x⁴ – 9x³ – 6x² + 8x + 3

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¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= – 2b⁴ + b³ – 11b² – 1

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– (– 3b⁴ – 3b³ – 5b² – 4b)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= 4b⁴ + 7b³ – b² + 8b – 1

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.... 4x⁴ + 8x³ + 16x² + 4

– (4x³ + 2x² + 16x)

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

= 4x⁴ – 4x³ + 14x² – 16x + 4

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