Put the numbers in order
9,32,65,69,76
Q1 = (32 + 9) / 2 = 41/2 = 20.5
Q2 = 65
Q3 = (69 + 76) / 2 = 145/2 = 72.5
now we find the IQR which is Q3 - Q1.....= 72.5 - 20.5 = 52
now we multiply 52 by 1.5....52 * 1.5 = 78
so the outliers will be :
Q1 - 78 .....20.5 - 78 = -57.5...anything below this
Q3 + 78.....72.5 + 78 = 150.5...anything above this
there is no outliers in here
Answer:
The probability is 25/216. Approximately 0.116
Step-by-step explanation:
You need
- The first throw to fail (probability 1-1/6 = 5/6)
- The second throw to fail (probability 5/5)
- The third throw to be a success (probability 1/6)
Since each throw is independent of the others, we have to multiply all probabilities to obtain the total probability of the event. Thus, the probability of requiring 3 rolls until getting doubles is
5/6 * 5/6 * 1/6 = 25/216 = 0.115741
This problem can also be solved with sophisticated theory;
the random variable which counts the number of tries until the first success is a geometric distribution. The only parameter of the distribution is the probability of success p. If X is geometric with parameter p, then the probability of X being equal to k (in other words, requiring k tries for a success) is
P(X = k) = (1-p)^(k-1) * p
If p = 1/6, then
P(X = 2) = (1-1/6)^2*(1/6) = (5/6)²*1/6 = 25/216
Answer:When the numerator degree is lower than the denominator degree, the horizontal asymptote will be y=0.
Step-by-step explanation:
As x gets really large or small the denominator will be much larger than the numerator, so y will be around 0.
Answer:
Oy=-x+5 2
Step-by-step explanation:
Answer:
(-2,3)
Step-by-step explanation:
You can see that the purple is the new triangle. So look at the coordinate of the D. You can see that it is plotted at (-2, 3)
