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2 years ago

What is an outlier in the data set 65, 32, 9, 76, 69?

1 answer:

6 0

Put the numbers in order
9,32,65,69,76
Q1 = (32 + 9) / 2 = 41/2 = 20.5
Q2 = 65
Q3 = (69 + 76) / 2 = 145/2 = 72.5

now we find the IQR which is Q3 - Q1.....= 72.5 - 20.5 = 52
now we multiply 52 by 1.5....52 * 1.5 = 78

so the outliers will be :
Q1 - 78 .....20.5 - 78 = -57.5...anything below this
Q3 + 78.....72.5 + 78 = 150.5...anything above this

there is no outliers in here

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alexgriva [62]

Answer:

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And

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Step-by-step explanation:

Given that,

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$9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$

$e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) } ]y = 0$

By comparing with y′+p(t)y=g(t), we get

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

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And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous.

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Answer:

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