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3 years ago

How to you multiply 1/10 X 1.4?

Mathematics

1 answer:

mash [69]3 years ago

7 0

Answer:

a. 1 ÷ 10 = 0.1

b. 0.1 x 1.4 = 0.14

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HELP THIS IS DUE IN 5 MINSSSSS! Mr. Viviano would like to report to the principal the smaller measure of center between the mean

sukhopar [10]

Answer:

The median. 80 because the mean is 80.454545

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

How do you work out the equation 1-x=9.

mafiozo [28]

Answer:

x=8

Step-by-step explanation:

x + 1 = 9

Simplifying

x + 1 = 9

Reorder the terms:

1 + x = 9

Solving

1 + x = 9

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.

1 + -1 + x = 9 + -1

Combine like terms: 1 + -1 = 0

0 + x = 9 + -1

x = 9 + -1

Combine like terms: 9 + -1 = 8

x = 8

Simplifying

x = 8

7 0

4 years ago

If the equation; (3x)² + {27 × (3)^1/k - 15}x + 4 = 0 has equal roots find k

Dima020 [189]

Step-by-step explanation:

$\green{\large\underline{\sf{Solution-}}}$

Given quadratic equation is

$\rm :\longmapsto\:\rm \: {(3x)}^{2} + \bigg(27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15 \bigg)x + 4 = 0$

can be rewritten as

$\rm :\longmapsto\:\rm \: {9x}^{2} + \bigg(27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15 \bigg)x + 4 = 0$

Concept Used :- 

Nature of roots :-

Let us consider a quadratic equation ax² + bx + c = 0, then nature of roots of quadratic equation depends upon Discriminant (D) of the quadratic equation.

If Discriminant, D > 0, then roots of the equation are real and unequal.

If Discriminant, D = 0, then roots of the equation are real and equal.

If Discriminant, D < 0, then roots of the equation are unreal or complex or imaginary.

Where,

Discriminant, D = b² - 4ac

Let's Solve this problem now!!!

On comparing with quadratic equation ax² + bx + c = 0, we get

$\red{\rm :\longmapsto\:a = 9}$

$\red{\rm :\longmapsto\:b = 27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15}$

$\red{\rm :\longmapsto\:c = 4}$

Since, Discriminant, D = 0

$\rm \implies\: {b}^{2} - 4ac = 0$

$\rm :\longmapsto\: {\bigg(27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15\bigg)}^{2} - 4 \times 4 \times 9 = 0$

$\rm :\longmapsto\: {\bigg(27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15\bigg)}^{2} - 144 = 0$

$\rm :\longmapsto\: {\bigg(27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15\bigg)}^{2} = 144$

$\rm :\longmapsto\: {\bigg(27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15\bigg)}^{2} = {12}^{2}$

$\rm \implies\:27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15 = \: \pm \: 12$

Case - 1

$\rm :\longmapsto\:27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15 = - 12$

$\rm :\longmapsto\:27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } = - 12 + 15$

$\rm :\longmapsto\:27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } = 3$

$\rm \implies\:{\bigg[3\bigg]}^{ \dfrac{1}{k} } = \dfrac{1}{9}$

$\rm \implies\:{\bigg[3\bigg]}^{ \dfrac{1}{k} } = \dfrac{1}{ {3}^{2} }$

$\rm \implies\:{\bigg[3\bigg]}^{ \dfrac{1}{k} } = {3}^{ - 2}$

$\rm \implies\:\dfrac{1}{k} = - 2$

$\bf\implies \:k \: = \: - \: \dfrac{1}{2}$

So, option (b) is Correct.

Case - 2

$\rm :\longmapsto\:27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } - 15 = 12$

$\rm :\longmapsto\:27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } = 12 + 15$

$\rm :\longmapsto\:27 \times {\bigg[3\bigg]}^{ \dfrac{1}{k} } = 27$

$\rm :\longmapsto\: {\bigg[3\bigg]}^{ \dfrac{1}{k} } = 1$

$\rm :\longmapsto\: {\bigg[3\bigg]}^{ \dfrac{1}{k} } = {3}^{0}$

$\rm \implies\:\dfrac{1}{k} =0$

which is not possible.

7 0

2 years ago

the track team is trying to reduce their time for a relay race. First they reduce their time by 2.1 minutes. then they are able

iVinArrow [24]

Answer:

The beginning time of relay race is 6.73 minutes

Step-by-step explanation:

Given as :

The final time of relay race = 3.96 minutes

Let The initial time of relay race = x minutes

At first, The time reduce by 2.1 min

So, The first time become = ( x - 2.1 ) min

At second , The time reduce by $\dfrac{1}{10}$ = 0.1

So, The time become = ( x - 2.1 ) min - $\dfrac{x}{10}$ min

$\dfrac{10 (x - 2.1) - x}{10}$

Or, $\dfrac{9 x - 21}{10}$

∵ final time of race = 3.96 min

∴ $\dfrac{9 x - 21}{10}$ = 3.96

Or, 9 x - 21 = 3.96 × 10

Or, 9 x = 39.6 + 21

Or, 9 x = 60.6

∴ x = $\dfrac{60.6}{9}$

i.e x = 6.73 minutes

So, The beginning time = x = 6.73 min

Hence,The beginning time of relay race is 6.73 minutes Answer

8 0

3 years ago

(Photo attached) Trig question. Please explain and thanks in advance! :)

Gennadij [26K]

Answer:

x ≈ 0.1459

Step-by-step explanation:

Since you only want a small positive solution, you can use the arcsine function to find it.

6sin(5x) = 4

sin(5x) = 4/6 = 2/3

5x = arcsin(2/3)

x = arcsin(2/3)/5

x ≈ 0.1459

_____

A graphing calculator can find the solution easily. It is often easiest to rewrite the equation so you're looking for a solution that makes the value zero. Here, subtracting 4 from both sides does that.

4 0

3 years ago