The error is that both sides of the equation have a variable. So if you were to combine your like terms, then you'd leave one side without a number and if your teacher is saying there is a left over number then it will be 0
Sometimes I’m pretty sure
Integration will be ln | ( x /9 ) + (
) | + c .
Given ∫ 1 dx / (
- 81 )
Put ,
x = 9 secθ
dx = 9 secθ tanθ dθ
and
= 9 tanθ
Substituting values in ∫ 1 dx / (
- 81 ) ,
∫ (9 secθ tanθ ) dθ / ( 9 tanθ )
∫ secθ dθ = ln | secθ + tanθ | + c
= ln | ( x /9 ) + (
/ 9 ) | + c
= ln | ( x /9 ) + (
) | + c
Hence , the integration will be ln | ( x /9 ) + (
) | + c .
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Answer:
Work out the number of boys and girls in each class below.
In class 8T, there are 9 boys.
The ratio of boys to girls is 1:2
Number of boys Number of girls = it's 0
1/3 x 4/4 = 4/12
4/12 + 5/12 = 9/12
12/12 - 9/12 = 3/12
3/12 = 1/4