Give two different ratios with a description of the ratio relationship using the

Mathematics

2 answers:

Sonbull [250]3 years ago

8 0

3:7
since the amount of teachers are in multiples of 5, you can just divide both by 5 to get a new simplified ratio

Shalnov [3]3 years ago

8 0

This has nothing to do with the question but with the adds it makes you watch you can skip them by putting your finger on the bar at the bottom and sliding your finger right :)

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PLEASE HELP ME THIS IS DUE TODAYYY

Vaselesa [24]

Answer:

Check the answers in the tables below

Step-by-step explanation:

First I will explain the steps done in each column

Column 1: Multiply 2 numbers

Column 2: Split the terms inside the bracket in such a way that adding or subtracting those numbers we get the same number.

Column 3: Using distributive property a(b+c) = (ab)+(ac)

Column 4: Solving the expression by adding or subtracting the terms

Given: Data in Column 2 100(0.04+0.06)

Column 1 Column 2 Column 3 Column 4 Value

100(0.1) 100(0.04+0.06) 100.0.04+100.0.06 4+6 10

Given: Data in column 3 $8.\frac{1}{2}+ 8.\frac{1}{4}$

Column 1 Column 2 Column 3 Column 4 Value

$8(\frac{3}{4})$ $8(\frac{1}{2}+\frac{1}{4})$ $8.\frac{1}{2}+ 8.\frac{1}{4}$ 4+2 8

Given: Data in Column 4 9+12

Column 1 Column 2 Column 3 Column 4 Value

3(7) 3(3+4) 3(3)+3(4) 9+12 21

Given: Data in Column 4 24-16

Column 1 Column 2 Column 3 Column 4 Value

4(2) 4(6-4) 4.6-4.4 24-16 8

4 0

3 years ago

Let U=[1,23,...,16] C=[1,3,5,...,15] Use the roster method to write the set C'.

Mazyrski [523]

The complement C' of some set C is essentially the set we get when we remove all of the elements of C from the universal set U.

Here, our universal set contains all of the numbers 1-16, and the set C contains all of the odd numbers between 1 and 16. If we were to put both of these sets in roster form:

$U=\{1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16\}\\C=\{1,3,5,7,9,11,13,15\}$

If we remove all of the elements of C from the universal set U, we're left with the complement of C, which contains all of the even numbers between 1 and 16:

$C'=\{2,4,6,8,10,12,14,16\}$