Question

If the endpoints of segment AB are A(-4,5) and B(2,-5),please help! ​

Answer 1

Answer:

$d = \sqrt[2]{34}$

Step-by-step explanation:

We are solving for the segment of AB. Note that it is a line segment, so there will be end points, those being A(-4, 5) & B(2, -5).

Use the following distance formula:

$distance$ $(d) =$ $\sqrt{(x_{2} - x_{1})^{2} + (y_{2} - x_{2})^2 }$

Let:

Point B(2 , -5) = (x₁ , y₁)

Point A(-4 , 5) = (x₂ , y₂)

Plug in the corresponding numbers to the corresponding variables.

$d =$ $\sqrt{(-4 - 2)^{2} + (5 - (-5))^{2} }$

Simplify. Remember to follow PEMDAS. First, solve the parenthesis, then the powers, then add, and then finally square root.

$d = \sqrt{(-6)^{2} + (5 + 5)^{2} } \\d = \sqrt{(-6 * -6) + (10)^2} \\d = \sqrt{(36) + (10 * 10)} \\d = \sqrt{36 + (100)} \\d = \sqrt{136}$

Simplify:

$d = \sqrt{136} = \sqrt{2 * 2 * 2 * 17} = \sqrt[2]{17 * 2} = \sqrt[2]{34}$

$d = \sqrt[2]{34}$ is your answer.

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