Question

Hello, please I bed urgent help with this math problem please

Answer 1

Answer:

option C

Step-by-step explanation:

$4c^2 + 7c - 5 = 0 , \ where \ a = 4 , \ b = 7 , \ x = - 5$

$c = \frac{- b \pm \sqrt{b^2 - 4ax }}{2a} \\\\c = \frac{- 7 \pm \sqrt{49 - ( 4 \times 4 \times - 5 )}}{2 \times 4} \\\\c = \frac{- 7 \pm \sqrt{49 + 80}}{8} \\\\c = \frac{- 7 \pm \sqrt{49 + 80}}{8} \\\\c = \frac{- 7 \pm \sqrt{129}}{8}$

Answer 2

Answer:

Option C

Step-by-step explanation:

Quadratic formula:

$4c^{2} +7c-5=0$

$a=4\\b=7\\x=-5$

$c=\frac{-b\frac{+}{} \sqrt{b^2-4ax}}{2a}$

$c=\frac{-7\frac{+}{}49-(4*4*-5) }{2*4}$

$c=\frac{-7\frac{+}{}\sqrt{129} }{8}$

hope this helps....