Need help with 3,4,5,6

Mathematics

1 answer:

LuckyWell [14K]3 years ago

4 0

The answers are:
3:d
4:c
5:b
6:c Note: I am not 100% sure.

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A coupon subtracts 5.16 from the price p of a shirt. you pay 15.48 for the shirt after using the coupon. write and solve an eqau

DochEvi [55]

15.48 + 5.16 = p because you have to do the reverse. to find "p" you have to add the amount you subtracted.

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3 years ago

jabu left town A to travel to town B at 6:00 a.m. he drove at an average speed of 80km/h. At 8.30a.m. Sipho left town A to trave

7nadin3 [17]

Answer:

Sipho catches up Jabu at 6:30 pm

Step-by-step explanation:

Jabu left town A to travel to town B at 6:00 a.m. he drove at an average speed of 80km/h.

At 8:30 am, when Sipho leaves, we will have traveled 2.5 hours at 80 km/h, so he will be 80*2.5 = 200 km ahead.

From then, his position will be given by:

$J(t) = 200 + 80t$

Sipho left town A to travel to town B. He drove at an average speed of 100 km/h.

His position will be given by:

$S(t) = 100t$

At what time will Sipho catch up jabu?

He will catch up in t hours, and t is found when:

$S(t) = J(t)$

$100t = 200 + 80t$

$20t = 200$

$t = \frac{200}{20} = 10$

He will catch up 10 hours after 8:30 am, that is, 6:30 pm.

Sipho catches up Jabu at 6:30 pm

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3 years ago

The following statement is either true (in all cases) or false (for at least one example). If false, construct a specific e

matrenka [14]

Answer:

False, counterexample below

Step-by-step explanation:

Denote the unit vectors of R^3 by $e_1=(1,0,0), e_2=(0,1,0), e_3=(0,0,1)$ . Now consider $v_1=e_1, v_2=2e_1$ and $v_3=e_3$ . We have that $v_1, v_2,v_3 \in \mathbb{R}^3$ . Also, the vector $v_3$ is not a linear combination of $v_1, v_2$ because any linear combination of these two vectors will have third coordinate zero, but v_3 has third coordinate 1 so they can't be equal.

However, the set $\{v_1, v_2,v_3\}$ is not linearly independent, because $2v_1-v_2+0v_3=0$ is a non-trivial linear combination of these vectors that equals zero.