Hope you could get an idea from here.
Doubt clarification - use comment section.
A^2=b^2+c^2-2bc Cos(A)
(270)^2=(255)^2+(442.85)^2-2(255)(442.85)Cos(A)
A=Cos^(-1)(270^2-255^2_(442.85)^2)/(-2*255*442.85)=33.5435
solve for angle A approximately is 33.54 degrees.
sinA/a=SinB/b
Sin33.54/270=SinB/255
B=Sin^(-1)(sin33.54/270*255)approximately is 31.45.
180-31.45-33.54=115.01 is Angle C.
Answer:
Soccer practice started at 6:00, because 7:15 - 1:15 = 6:00
Answer:
Step-by-step explanation:
Remark
The angle formed by the intersection of a tangent to a circle and an intersecting secant is 1/2 (Arc PS - arc PR)
PS = 208
PR = 74
Solution
x = 1/2 (208 - 74)
x = 1/2 (134)
x = 67
1.
558 can be rounded to 600.
44 can be rounded to 40.
600 x 40 = 24,000
2.
9 x 802 = 9 (800 +2) =7200 + 18 = 7218
3.
3699 x 7 = (3700-1) x 7 = 25,900 - 7 = 25,893
4.
34 x 93 = 34 x (100-7) = 3400 - 238 = 3162
5.
678 x 87 = 58,986
