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Anna35 [415]
3 years ago
13

The top and bottom ends of a windshield wiper blade are R = 24 in. and r = 14 in., respectively, from the pivot point. While in

operation, the wiper sweeps through 135°. Find the area swept by the blade. (Round your answer to the nearest whole number.)
Mathematics
1 answer:
Orlov [11]3 years ago
3 0

Answer:

Area swept by the blade = 448in^{2}

Step-by-step explanation:

The arc the wiper wipes is for 135 degrees angle.

So, find area of sector with radius 24 inches. And the find area of arc with r=14 inches.

Then subtract the area of sector with 14 inches  from area of sector with radius as 24 inches.

So, area of sector with r=24 in =\frac{135}{360} *\pi  *24^{2}

Simplify it,

                                                  =216\pi

Now, let's find area of sector with radius 14 inches

Area of sector with r=14 in = \frac{135}{360} *\pi  *14^{2}

Simplify it

                                          =73.5\pi

So, area swept by the blade = 216\pi -73.5\pi

Simplify it and use pi as 3.14.....

Area of swept =678.584 - 230.907

                               =447.6769

Round to nearest whole number

So, area swept by the blade = 448in^{2}

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A normal window is constructed by adjoining a semicircle to the top of an ordinary rectangular window, (see figure ) The perimet
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Let's find the perimeter of the window.

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We only want to use one variable to create the area formula, so let's solve for y.

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A_r=x(6-\frac{1}2x-\frac{1}4\pi x

A_r=6x-\frac{1}2x^2-\frac{1}4\pi x^2

The area of the semicircle is going to be \frac{1}2\pi r^2.

Since r=\frac{1}2x, A_{sc}=\frac{1}2\pi (\frac{1}2x)^2.

A_{sc}=\frac{1}2\pi \frac{1}4x^2

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Now let's add the areas of the rectangle and semicircle.

A=A_r+A_{sc}

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A=6x-\frac{1}2x^2-\frac{1}8\pi x^2

If you wanted to factor out \frac{1}8 like you did, this would become

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Now what we want to do is find what x is when A is at its highest point, Once we have the value for x we can also find the value for y, of course.

Let's put our equation in the general form of a quadratic.

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x=\frac{-6}{2(-\frac{1}2-\frac{1}8\pi)}

x=\frac{-6}{-\frac{1}4\pi -1}

x=\frac{-24}{-\pi -4}

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Since our final answers are in decimal form and not exact form, we can make our lives a little easier here and just use x\approx3.36059492.

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<span>y\approx6-(1.68029746+2.63940507809)

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\boxed{x\approx 3.36\ ft}

\boxed{y\approx 1.68\ ft}</span>
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