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vovikov84 [41]
3 years ago
9

Find csc0 Please Help!!!!!

Mathematics
2 answers:
andreyandreev [35.5K]3 years ago
7 0
<h3>Answer:  -5/4</h3>

=======================================================

Explanation:

The terminal point is at (x,y) = (3,-4)

Apply the pythagorean theorem to find that x^2+y^2 = r^2 solves to r = 5. This is the length of the hypotenuse.

Then we can determine the cosecant of the angle theta using the formula below

csc(theta) = hypotenuse/opposite

csc(theta) = r/y

csc(theta) = 5/(-4)

csc(theta) = -5/4

Side note: csc = 1/sin

dexar [7]3 years ago
3 0
-5/4 maybe is the correct answer
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3 years ago
How do you answer this following equation “ the sum of two numbers is 33 , and the sum of 7 times the first number and 5 times t
nadya68 [22]

\bf \begin{cases} a\\\\ b \end{cases}\qquad \qquad \begin{array}{llll} \stackrel{\textit{the sum of \underline{a} and \underline{b}}}{a+b=33}\\\\ \stackrel{\textit{the sum of 7 times \underline{a} and 5 times \underline{b}}}{7a+5b=197} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ a+b=33\implies \boxed{b}=33-a \\\\\\ \stackrel{\textit{substituting \boxed{b} in the second equation}}{7a+5\left(\boxed{33-a} \right)=197}\implies 7a+165-5a=197


\bf 2a+165=197\implies 2a=32\implies a=\cfrac{32}{2}\implies \blacktriangleright a=16 \blacktriangleleft \\\\\\ \boxed{b}=33-a\implies b=33-16\implies \blacktriangleright 17\blacktriangleleft

4 0
3 years ago
A ladder 5 feet long leans against a wall and makes an angle of 65% with the ground. a. Find, to the nearest tenth of a foot, th
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Step-by-step explanation:

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The distance, d from the bottom of the ladder to the base of the wall represents the adjacent side of the right angle triangle.

To determine the distance, d from the bottom of the ladder to the base of the wall, we would apply we would apply the cosine trigonometric ratio.

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d = 2.1 feet

7 0
3 years ago
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