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kupik [55]
3 years ago
13

Find the volume of the figure

Mathematics
1 answer:
Charra [1.4K]3 years ago
7 0
8*10*14 = 1120
10*8*10 = 800
1120+800 = 1920
volume =1920 cm3
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Simplify (x - y + 1) - (x + y - 1)
andrey2020 [161]
First, distribute the minus sign across the second set. So you have:

x - y + 1 - x - y + 1

Now, we combine like terms:
x-x=0
-y-y=-2y
1+1=2

So we have -2y+2

Hope that helps.
5 0
3 years ago
Question 1(Multiple Choice Worth 1 points)
Galina-37 [17]

Answer:

The answer is b. x= 2, -1

5 0
3 years ago
The area of rectangular is 64m the length of the pool is 12 m less that the width .The situation can be represented by the equat
beks73 [17]

Answer:

Width = 16 m

Length = 4 m

Step-by-step explanation:

The area of rectangular is 64m² the length of the pool is 12 m less that the width . The situation can be represented by the equation x

Area of a rectangle = Length × Width

L = W - 12

Hence:

64 = (W - 12) × W

64 = W² - 12W

W² - 12W - 64 = 0

Factor using

(W + 4)(W - 16) = 0

Width = 16m

Length = W - 12

Length = 16 m - 12 m

= 4 m

6 0
3 years ago
Old time savings bank pays 4% interest on its savings accounts. if you deposit $1,000 in the bank and leave it there: (do not ro
topjm [15]
A. $40, because you would do 1,000 × 1.04 = $1,040, and then subtract the original $1,000.
b. $81.60, because 1,000 × 1.04² = 1,081.6
c. $480.24, because 1,000 × 1.04^10 = 1,480.24.
I have used the formula for compound interest presuming you were aware of it, but I will be happy to explain what I did if you want :).
I hope this helps!
3 0
3 years ago
Read 2 more answers
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
fenix001 [56]

Answer:

x^6y^3

Step-by-step explanation:

<u>Given polynomial:</u>

  • 8x^6y^5 - 3x^8y^3

<u>Get prime factors:</u>

  • 2*2*2*x*x*x*x*x*x*y*y*y*y*y - 3*x*x*x*x*x*x*x*x*y*y*y

<u>Common factors of the two terms:</u>

  • x*x*x*x*x*x*y*y*y = x^6y^3

<u>So</u>

  • x^6y^3(8y^2 - 3x^2)

x^6y^3 is the GCF of this polynomial

4 0
3 years ago
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