Answer:
2x^2(x^3+3x+8)
Step-by-step explanation:
Factor out the gcf which in this case is -2x^2 because that's the greatest factor all of the terms have in common this results in -2x^2(x^3+3x+8)
Btw the ^ represents the exponent
Answer:
not
Step-by-step explanation:
![\left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] *\left[\begin{array}{ccc}-2&1\\3&7\end{array}\right]=](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%264%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D%20%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%261%5C%5C3%267%5Cend%7Barray%7D%5Cright%5D%3D)
First is A and Second is B
Let's find A*B
![\left[\begin{array}{ccc}-2(-2)+4*3&-2*1+4*7\\1(-2)+3*3&1*1+3*7\end{array}\right] =\left[\begin{array}{ccc}16&26\\7&22\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%28-2%29%2B4%2A3%26-2%2A1%2B4%2A7%5C%5C1%28-2%29%2B3%2A3%261%2A1%2B3%2A7%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%2626%5C%5C7%2622%5Cend%7Barray%7D%5Cright%5D)
b)
![\left[\begin{array}{ccc}-2&1\\3&7\end{array}\right] \left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] =](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%261%5C%5C3%267%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%264%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D%20%3D)
Now let's find B*A
![\left[\begin{array}{ccc}-2(-2)+1*1&-2*4+1*3\\3(-2)+7*1&3*4+7*3\end{array}\right] =\left[\begin{array}{ccc}5&-5\\1&23\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%28-2%29%2B1%2A1%26-2%2A4%2B1%2A3%5C%5C3%28-2%29%2B7%2A1%263%2A4%2B7%2A3%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-5%5C%5C1%2623%5Cend%7Barray%7D%5Cright%5D)
c) They are not
Since we are given with the identity of the chemical as Carbon-14, we obtain the half-life of the chemical from a reliable source and get a value of 5730 years. The equation that we are going to use for this item is,
A(t)/A(0) = (0.50)^(n/5730)
where A(t) is the current amount, A(0) is the initial amount and n is the number of years. We know from the given that the ratio of A(t) and A(0) is equal to 0.63. Substituting this to the given,
0.63 = 0.50^(n/5730)
n = 3819.48
Thus, the sample is approximately 3819.5 years old.
Answer:
Step-by-step explanation:
One number is 2 more than 3 times another. Their sum is 14.Find the numbers. 8, 14 5, 17 2, 20 4, 18 10, 12
Usually when you add big numbers together, you get a result of exponents involved :) answer for your question : 1.212154551 e^22
