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3 years ago

7

Dont answer this PLEAS

1 answer:

pickupchik [31]3 years ago

5 0

Answer:

why? also the answer is 1.6y+y-4/15y+7/6y=21/3

We move all terms to the left:

1.6y+y-4/15y+7/6y-(21/3)=0

Domain of the equation: 15y!=0

y!=0/15

y!=0

y∈R

Domain of the equation: 6y!=0

y!=0/6

y!=0

y∈R

We add all the numbers together, and all the variables

1.6y+y-4/15y+7/6y-7=0

We add all the numbers together, and all the variables

2.6y-4/15y+7/6y-7=0

We calculate fractions

2.6y+(-24y)/90y^2+105y/90y^2-7=0

We multiply all the terms by the denominator

(2.6y)*90y^2+(-24y)+105y-7*90y^2=0

We add all the numbers together, and all the variables

(+2.6y)*90y^2+(-24y)+105y-7*90y^2=0

We add all the numbers together, and all the variables

105y+(+2.6y)*90y^2+(-24y)-7*90y^2=0

Wy multiply elements

-630y^2+105y+(+2.6y)*90y^2+(-24y)=0

We get rid of parentheses

-630y^2+105y+(+2.6y)*90y^2-24y=0

We add all the numbers together, and all the variables

-630y^2+81y+(+2.6y)*90y^2=0

Step-by-step explanation:

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A student claims that -4i is the only imaginary root of a quadratic polynomial equation that has real coefficients.

Nat2105 [25]

Answer:

If a quadratic equation has an imaginary root -4i, then its conjugate i.e. 4i will be the other root of the equation.

$x^{2} + 16 = 0$

Step-by-step explanation:

a. The only imaginary root of a quadratic equation is -4i, this is not possible.

Because, if a quadratic equation has an imaginary root -4i, then it's conjugate i.e. 4i will be the other root of the equation.

b. So, the two roots of a quadratic equation are imaginary and they are 4i and -4i.

Therefore, the equation will be

(x - 4i)(x + 4i) = 0

⇒ $x^{2} - (4i)^{2} = 0$

⇒ $x^{2} - (- 16) = 0$

⇒ $x^{2} + 16 = 0$ (Answer)

4 0

4 years ago

Excluding trailing zeroes, how many digits does 0.4^24 x 0.375^22 have to the right of the decimal point? Please explain.

Alex787 [66]

I believe the answer to this is zero but I am not 100 percent sure.

3 0

3 years ago

Read 2 more answers

Trigonometry Problem, only solve if you know how and can tell me how to solve it.

Crazy boy [7]

The distances from the point the plane leaves the ground are given by the

trigonometric relationships of right triangle and Pythagoras theorem.

A) The minimum distance to the base of the tower is approximately <u>874.57 ft</u>.

B) The minimum distance to the top of the tower is approximately <u>882.76 ft</u>.

Reasons:

A) The angle with which the airplane climbs, θ = 11°

Height of the tower which the airplane flies, T = 120 foot

The clearance between the tower and the airplane, C = 50 feet

Required:

The minimum distance between the point where the plane leaves the ground and the base of the tower, $\displaystyle d_{min}}$

Solution:

Height at which the plane flies over the tower, h = T + C

Therefore, h = 120 ft. + 50 ft. = 170 ft.

At the point the plane leaves the ground, we have;

$\displaystyle tan(\theta) = \mathbf{\frac{h}{d_{min}}}$

Which gives;

$\displaystyle tan(11^{\circ}) = \frac{170 \, ft.}{d_{min}}$

$\displaystyle d_{min} = \mathbf{\frac{170 \, ft.}{tan(11^{\circ})}} \approx 874.57 ft.$

The minimum distance between the point where the plane leaves the ground and the base of the tower, $\displaystyle d_{min}}$ ≈ <u>874.57 ft</u>.

B) The minimum distance between the point where the plane leaves the ground and the tower, <em>R</em>, is given by Pythagoras's theorem as follows;

R² = $\displaystyle \mathbf{d_{min}}}$ ² + T²

Which gives;

R = √(*874.57 ft.)² + (120 ft.²)) ≈ 882.76 ft.

The distance from the point where the airplane leaves the ground to the tower, R ≈ <u>882.76 ft</u>.

Learn more about Pythagoras theorem here:

brainly.com/question/11256912

7 0

2 years ago

Gabriel deposits $2,500 into each of two savings accounts.

charle [14.2K]

Answer:

$5,612.16

Step-by-step explanation:

Part 1) Account I earns 4% annual simple interest.

we know that

The simple interest formula is equal to

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest

t is Number of Time Periods

in this problem we have

substitute in the formula above

Part 2) Account II earns 4% interest compounded annually.

we know that

The compound interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

t=3 years

p=$2,500

r=4%=4/100=0.04

substitute in the formula above

A=2,500(1+0.04 * 3)

A=2,500 (1.12)

A=$2,800

Part 3) What is the sum of the balances of Account I and Account II at the end of 3 years?

Sum the two final investment

$2,800 + $2,812.16 = $5.612.16

8 0

4 years ago

Challenge A bag contains pennies, nickels, dimes, and quarters. There are 50 coins in all. Of the coins, % are pennies and

Semmy [17]

Answer:

.

10% of 50 coins is/are 5 coins. So, 5 coins are pennies.

40% of 50 coins is/are 20 coins. So, 20 coins are dimes.

The number of nickels is (5 + 9) = 14, according to the condition.

Then quarters are the rest (50 - 5 - 20 - 14) = 11 coins.

Now you can easily calculate the total and answer the question

Total = 5*1 + 14*5 + 20*10 + 11*25 = 550 cents = $5.50. ANSWER

Step-by-step explanation:

5 0

3 years ago