Answer:
a1 = 2
d = 3
an = 2 + (n - 1) * 3
a7 = 20
a59 = 176
Steps:
a1 is the initial value (when n equals 1), and since there are 2 crosses, it is 2.
d is the added value to each amount of crosses. And since the second amount is 5 and the third amount is 8, we can determine that each n is adding 3 crosses, therefore making d = 3.
The equation is simply plugging in the values for a1 and d.
A7 is simply plugging in 7 for n in the equation and solving for it. So;
a7 = 2 + (7 - 1) * 3
a7 = 2 + 6 * 3
a7 = 2 + 18
a7 = 20
And same thing as the last for 59 except substitute 59 in for where you put 7;
a59 = 2 + (59 - 1) * 3
a59 = 2 + 58 * 3
a59 = 2 + 174
a59 = 176
Answer: Postulate means a fact or a truth of something
Step-by-step explanation:
Answer:
1 2 = 2 4 = 3 6 = 4 8 = etc. All of these fractions are located at the same point on the number line. Therefore, they represent the same number. From the paper folding exercises, we see that increasing both numerator and denominator of a fraction by the same factor gives an equivalent or equal fraction.
Hope this helps :) Just know I tried.
Answer:
Unfortunately I can't read your answer options properly. The copied text is just too messed up. But hopefully the step-by-step calculation will help you.
Lemme know if it worked for you and if you have further questions.
Step-by-step explanation:
3x - 2y = -6
can be rewritten as
2y = 3x + 6
or simpler
y = 1.5x + 3
we know that it's parallel to this line, but we don't know how much lower or higher the new line will be, so let's set "+3" as an unknown variable.
y = 1.5x + b
(the letter b is now what we try to solve for)
now let's plug in the x-/y-Informations of the given point
2 = 1.5 * 4 + b
2 = 6 + b
-4 = b
so the new line is
y = 1.5x -4
(the given point lies on that line and it's parallel to the other line)
let's multiply everything by two to get closer to the original format
2y = 3x -8
it could also be expressed as
2y = -(-3x+8)
(in hope that this may help for choosing an answer option)
please clean up the text of questions before posting next time
(would really appreciate the brainliest)
