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lapo4ka [179]
3 years ago
11

URGENT HELP The nth term of a sequence is given 3n-16. What’s the value of the 9th term?

Mathematics
1 answer:
Ivan3 years ago
7 0

Answer:

a₉ = 11

Step-by-step explanation:

Substitute n = 9 into the nth term formula, that is

a₉ = 3(9) - 16 = 27 - 16 = 11

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The question is in the image below.
sineoko [7]

Answer:

The Recursive Formula for the sequence is:

\:a_n=\frac{1}{5}\left(a_{n-1}\right)     ; a₁ = 125

Hence, option D is correct.

Step-by-step explanation:

We know that a geometric sequence has a constant ratio 'r'.

The formula for the nth term of the geometric sequence is

a_n=a_1\cdot r^{n-1}

where

aₙ is the nth term of the sequence

a₁ is the first term of the sequence

r is the common ratio

We are given the explicit formula for the geometric sequence such as:

a_n=125\left(\frac{1}{5}\right)^{n-1}

comparing with the nth term of the sequence, we get

a₁ = 125

r = 1/5

Recursive Formula:

We already know that

  • a₁ = 125
  • r = 1/5

We know that each successive term in the geometric sequence is 'r' times the previous term where 'r' is the common ratio.

i.e.

a_n=ra_{n-1}

Thus, substituting r = 1/5

\:a_n=\frac{1}{5}\left(a_{n-1}\right)  

and a₁ = 125.

Therefore, the Recursive Formula for the sequence is:

\:a_n=\frac{1}{5}\left(a_{n-1}\right)     ; a₁ = 125

Hence, option D is correct.

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