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lapo4ka [179]
3 years ago
11

URGENT HELP The nth term of a sequence is given 3n-16. What’s the value of the 9th term?

Mathematics
1 answer:
Ivan3 years ago
7 0

Answer:

a₉ = 11

Step-by-step explanation:

Substitute n = 9 into the nth term formula, that is

a₉ = 3(9) - 16 = 27 - 16 = 11

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So far this month John calculated that he will earn $40 in comission for his $500 in product sales. If John would like his comis
Helen [10]

John made $40 commissions for $500 sales or 40/500. He wants $320 for an unknown amount of sales or 320/x.

40/500=320/x Cross multiply.

40x=160,000

Divide both sides by 40.

X=4,000

He needs his sales to be $4,000 to get $320 in commission.

4 0
3 years ago
Rewrite the following equation in slope-intercept form.<br><br> x + 4y = 16
baherus [9]

Answer:

y=-x/4+4

Step-by-step explanation:

Slope intercept form: y=mx+b

x+4y=16

4y=-x+16

y=-x/4+4

6 0
3 years ago
Read 2 more answers
HELP DISTRIBUTIVE PROPERTY QUADRATICS PLZZZZZZZ
Vlad1618 [11]
1: x² + 10x + 25
2: x² - x -12
3: -2x² + 10x
4: -2x² + 9x + 5
5: n² - 4
---------------------------
1: x² + 14x + 49
2: x² - 14x + 49
3: 4n² - 20n + 25
4: 4n² + 20n +25
5: you just have to switch the signs
4 0
3 years ago
Suppose that f : [a, b] → [a, b] is continuous. Prove that f has a fixed point. That is, prove that there exists c ∈ [a, b] such
nikklg [1K]

Answer:

Step-by-step explanation:

define the function:

g(x) = f(x) -x

As both f(x) and x are continuous functions, g(x) will also be continuous.

Now, what can we say about g(a) = f(a) -a?

we know that a\leq f(a) \leq b, thus:

a-a\leq f(a)-a \leq b-a\\0 \leq g(a) \leq b-a

thus  g(a) is non-negative.

What about g(b) ? Again we have:

a\leq f(b) \leq b\\a-b \leq f(b) -b \leq  0\\a-b \leq g(b) \leq  0

That means that g(b) is not positive.

Now, we can imagine two cases, either one of g(a) or g(b) is equal to zero, or none of them is. If either of them is equal to zero, we have found a fixed point! In fact, any point c for which g(c)=0 is a fixed point, because:

g(c) = 0 \implies f(c) -c = 0 \implies f(c) = c

Now, if g(a) \neq  0 and g(b) \neq 0, then we have that

g(a) >0 and g(b) < 0. And by Bolzano's theorem we can assert that there must exist a point c between a and b for which g(c)=0. And as we have shown before that point would be a fixed point. This completes the proof.

6 0
3 years ago
The length of a rectangle is 4 cm longer than its width. If the perimeter of the rectangle is 40 cm, find its area
mel-nik [20]

Answer:

96

Step-by-step explanation:

The length of a rectangle is 4 cm longer than its width. If the perimeter of the rectangle is 40 cm, find its area

width + 4 = length

width = width

2l + 2w = p

width+width +width +width +4 +4 = 40

4width +8  = 40

4width =  32

width = 8

length x width = area

width = 8

length = 12 (width + 4)

12x 8 =  96

<h2><u><em>have a great day! I hope this helped! :)</em></u></h2>

3 0
3 years ago
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