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aalyn [17]
4 years ago
9

If rectangle DEFG is dilated by a scale factor of 3 with a dilation center of (0, 0), what will be the coordinates of point D'?

Mathematics
2 answers:
Finger [1]4 years ago
4 0

Answer:

C). (-6, -3)

Step-by-step explanation:

We have been given a rectangle DEFG on coordinate plane. We are asked to find the coordinates of point D after a dilation by a scale factor of 3 with center of dilation at origin (0,0).

Since dilating a figure by a scale factor (k), we multiply the coordinates of all points of the figure by the scale factor k.

(x,y)\rightarrow (kx,ky)

We can see that coordinates of point D are (-2,-1). After dilation by scale factor  of 3 coordinates of D will be:

(3\cdot -2, 3\cdot -1)\rightarrow (-6,-3)

Therefore, the coordinates of point D will be (-6,-3) and option C is the correct choice.

ser-zykov [4K]4 years ago
3 0
The coordinate of D is (-2, -1)
applying a scale factor of 3 through a dilation would mean you would have to multiply the coordinate values by the scale factor which would result in (-6,-2)
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Find the area of the triangle. Choices- Question 8 options: a) 70 units2 b) 35 units2 c) 28 units2 d) 14 units2
viva [34]

Answer:

35 (b)

Step-by-step explanation:

Area of a triangle = (height times base)/2

Height = 5

Base = 14

14 times 5 = 70

70/2 = 35

3 0
3 years ago
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Chris and Dave and Ed share £720 between them. Chris receives £90 more than Dave. The ratio of Chris's share to Dave's share is
jolli1 [7]

Answer:

Ratio of Ed's share :  Dave's share  = 4 : 5

Step-by-step explanation:

Total amount shared =  £720

Let us assume that Dave receives =  £m

So, Chris's share = £90 + m

Also, Chris's share : Dave's Share = 7: 5

⇒\frac{90 + m}{m}  = \frac{7}{5}

Here, solving for m , we get :  5(90 + m) = 7m

or,  450 + 5m = 7m

⇒ 2m = 450, ⇒ m = 225

So, Dave's Share =  m = £225

Chris's share = £90 + m = 225 + 90  = £ 315

Hence, Ed's share = Total - ( sum of Dave's and Chris's share)

= 720 -( 315 + 225) = £180

So, ratio of Ed's share :  Dave's share = £180 : £225

or, Ratio of Ed's share :  Dave's share  = 4: 5

7 0
4 years ago
8.The weight distribution of parcels sent in a certain manner is normal with mean value 12lb and standard deviation 3.5 lb. The
Sladkaya [172]

Answer:

The value is c = 21.1445.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The weight distribution of parcels sent in a certain manner is normal with mean value 12lb and standard deviation 3.5 lb.

This means that \mu = 12, \sigma = 3.5

What value of c is such that 99% of all parcels are at least 1 lb under the surcharge weight?

This 1 added to the value of X for the 99th percentile, which is X when Z has a p-value of 0.99, so X when Z = 2.327.

Z = \frac{X - \mu}{\sigma}

2.327 = \frac{X - 12}{3.5}

X - 12 = 2.327*3.5

X = 20.1445

1 + 20.1445 = 21.1445

The value is c = 21.1445.

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