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3 years ago

13

For each journey between work and home, Arjun uses 1.3 gallons of petrol. Arjun has 52 litres of petrol in his car. How many com

plete journeys between work and home can he do?
1 gallon = 4.5 litres.

1 answer:

son4ous [18]3 years ago

5 0

Answer: 9 full journeys

Step-by-step explanation:

4.5 litres * 1.3 gallons = 5.8 litres of petrol

52 litres ÷ 5.8 litres of petrol = 8.9 journeys ≈ 9 full journeys

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two blocks of wood are shaped as right rectangle prisms the smaller block has a length of 9 cm a width of 3 cm and a height of 7

dolphi86 [110]

Answer:

1,512 cm³

Step-by-step explanation:

The general formula for the volume of a prism is:

V= Bh, where B = the area of the base and h = height of the prism

Given the dimensions of the smaller block as 9cm x 3cm x 7cm, then the dimensions of the larger block (double the dimensions of the smaller block) must be 18cm x 6cm x 14cm. Using these measurements:

V = (18)(6)(14) = 1,512 cm³

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4 years ago

What is the greatest common factor of each set of numbers. 30,48,60___

blondinia [14]

The GCF of those 3 is 6

4 0

3 years ago

The number of entrants in the boston marathon was recorded

Maru [420]

31302 is my guestimate.

3 0

3 years ago

The friendly sausage factory (fsf) can produce hot dogs at a rate of 5,000 per day. fsf supplies hot dogs to local restaurants a

juin [17]

Answer:

a. 21 327 hot dogs/run

b. 70 runs/yr

c. 4 da/run

Step-by-step explanation:

Data:

Production rate (p) = 5000/da

Usage rate (u) = 260/da

Setup cost (S) = $66

Annual carrying cost (H) = $0.45/hot dog

Production days (d) = 294 da

Calculations:

a. Optimal run size

(i) Annual demand (D) = pd = (5000 hot dogs/1 day) × (294 days/1 yr)

= 1 470 000 hot dogs/yr

(ii) Economic run size

$Q_{0}= \sqrt{\frac{2DS }{ h}\times\frac{ p}{p-u }}$

$= \sqrt{\frac{2\times1470000\times66 }{ 0.45}\times\frac{ 5000}{5000-260 }}$

$= \sqrt{431200000\times\frac{ 5000}{4740 }}$

$= \sqrt{454852321}$

= 21 327 hot dogs/run

b. Number of runs per year

Runs = D/Q₀ = (1 470 000 hot dogs/1yr) × (1 run/21 327 hotdogs)

= 70 runs/yr

c. Length of a run

Length = Q₀/p = (21 327 hot dogs/1 run) × (1 da/5000 hot dogs)

= 4 da/run

8 0

3 years ago

Find the percent of increase to the nearest whole from 12 to 20

ankoles [38]

Answer:

The answer is

<h2> $67\%$ </h2>

Step-by-step explanation:

To find the percentage increase we use the formula

<h3> $Percentage \: change = \frac{change}{original \: \: quantity} \times 100\%$ </h3>

From the question

The original value = 12

To find the change we subtract the smaller value from the larger one

That's

Change = 20 - 12 = 8

So the percentage increase is

<h3> $\frac{8}{12} \times 100 \%\\ = \frac{2}{3} \times 100\% \\ = 66.67\%$ </h3>

We have the final answer as

$67\%$ to the nearest whole number

Hope this helps you

3 0

3 years ago