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pickupchik [31]
2 years ago
5

Solve the system of linear equations. −x+2y=7 x−2y=7

Mathematics
2 answers:
ivolga24 [154]2 years ago
6 0
The answer is no solution.
hope that helps!
gregori [183]2 years ago
5 0
The answer is infinity *no solution*
have a good day!
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It is given that y varies inversely as x^2. If x is decreased by 50%, find the percentage change in y.
vova2212 [387]

Answer:

300%

Step-by-step explanation:

Given

y\ \alpha\ \frac{1}{x^2}

Required

Find the percentage change in y when x decreased by 50%

First, convert to equation

y\ = \ \frac{k}{x^2}

Where k is the constant of proportionality

When x decreased by 50%

Y = \frac{k}{(x - 0.5x)^2}

Y = \frac{k}{(0.5x)^2}

Y = \frac{k}{0.25x^2}

Expand

Y = \frac{1}{0.25} * \frac{k}{x^2}

Substitute \frac{k}{x^2} for y

Y = \frac{1}{0.25} * y

Y = 4 * y

Y = 4 y

The percentage change is then calculated as:

\%Change = \frac{Y - y}{y} * 100\%

\%Change = \frac{4y - y}{y} * 100\%

\%Change = \frac{3y}{y} * 100\%

\%Change = 3 * 100\%

\%Change = 300\%

<em>The percentage in y is 300%</em>

7 0
3 years ago
I would like to create a rectangular vegetable patch. The fencing for the east and west sides costs $4 per foot, and the fencing
Anestetic [448]
Let the lengths of the east and west sides be x and the lengths of the north and south sides be y.  the dimensions you want are therefore x and y.

The cost of the east and west fencing is $4*2*x; the cost of the north and south fencing is $2*2*y.  We have to put in that "2" because there are 2 sides that run from east to west and 2 sides that run from north to south.



The total cost of all this fencing is $4(2)(x) + $2(2)(y) = $128.  Let's reduce this by dividing all three terms by 4:  2x + y = 32.

Now we are to maximize the area of the vegetable patch, subject to the constraint that 2x + y = 32.  The formula for area is A = L * W.  Solving 2x + y = 32 for y, we get y = -2x + 32.

We can now eliminate y.  The area of the patch is (x)(-2x+32) = A.  We want to maximize A.

If you're in algebra, find the x-coordinate of the vertex of this quadratic equation.  Remember the formula x = -b/(2a)?  Once you have calculated this x, subst. your value into the formula for y:  y= -2x + 32.

Now multiply together your x and y values to obtain the max area of the patch.


If you're in calculus, differentiate A = x(-2x+32) with respect to x and set the derivative equal to zero.  This approach should give you the same x value as before; the corresponding y value will be the same;  y=-2x+32.

Multiply x and y together.  That'll give you the maximum possible area of the garden patch.
5 0
3 years ago
Solve -7w + 6 = -4w2 using the Quadratic Formula.<br> W =<br> and w=
marishachu [46]

Answer:

w=7±i√47

-----------

   8

Step-by-step explanation:

4 0
3 years ago
Evaluate (2a-4)2+10 for a=3<br> PLEASE
givi [52]

Answer:

14

Step-by-step explanation:

sorry if it not correct ._.

6 0
3 years ago
Determine the values of n and m so that the following system have infinite number of solutions
cupoosta [38]

Answer:

n = 3

m = -1/2

Step-by-step explanation:

Multiply the second equation by 4

4(n - 2)x + y = 4(n + m)          Y is now correct.

4(n - 2) = 4                              Remove the brackets    

4n - 8 = 4                                Add 8 to both sides

4n = 8 + 4                               Combine

4n = 12                                    Divide by 4

n = 3                                        x is now correct

4(n - 2) = 4

4(3 -2) = 4

4 = 4

Now you have to worry about m

4(n + m) = 10

n = 3

4(3 + m) = 10                               Divide by 4

m + 3 = 10/4

m + 3 = 2.5                                 Subtract 3 from both sides.

m = 2.5 - 3

m = - 1/2  

6 0
3 years ago
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