Question

What is the P(A and B) given that P(A) = 0.53, P(B) = 0.39, and P(A or B) = 0.48

Answer 1

Answer:

P(A and B) = 0.44

Step-by-step explanation:

Venn probabilities:

Suppose that we have two events, A and B. The probability of A and B is:

$P(A \cap B) = P(A) + P(B) - P(A \cup B)$

In which $P(A \cup B)$ is P(A or B).

In this question:

$P(A) = 0.53, P(B) = 0.39, P(A \cup B) = 0.48$

Then

$P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.53 + 0.39 - 0.48 = 0.44$

So

P(A and B) = 0.44