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pantera1 [17]
3 years ago
5

What is the P(A and B) given that P(A) = 0.53, P(B) = 0.39, and P(A or B) = 0.48

Mathematics
1 answer:
igor_vitrenko [27]3 years ago
6 0

Answer:

P(A and B) = 0.44

Step-by-step explanation:

Venn probabilities:

Suppose that we have two events, A and B. The probability of A and B is:

P(A \cap B) = P(A) + P(B) - P(A \cup B)

In which P(A \cup B) is P(A or B).

In this question:

P(A) = 0.53, P(B) = 0.39, P(A \cup B) = 0.48

Then

P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.53 + 0.39 - 0.48 = 0.44

So

P(A and B) = 0.44

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Use the Distributive Property to simplify the following expression <br> -2 (x + 3)
Dmitry_Shevchenko [17]

Answer:

-2x-6

Step-by-step explanation:

-2(×+3)

-2x-2.3

-2x-6

4 0
3 years ago
WILL GIVE BRAINLY PLEASE HELP!!!!!!!
marta [7]

Answer:

r² = 0.5652  < 0.7 therefore, the correlation between the variables does not imply causation

Step-by-step explanation:

The data points are;

X,          Y

0.7,       1.11

21.9,     3.69

18,         4

16.7,      3.21

18,         3.7

13.8,      1.42

18,          4

13.8,      1.42

15.5,      3.92

16.7,       3.21

The correlation between the values is given by the relation

Y =   b·X + a

b = \dfrac{N\sum XY - \left (\sum X  \right )\left (\sum Y  \right )}{N\sum X^{2} - \left (\sum X  \right )^{2}}

a = \dfrac{\sum Y - b\sum X}{N}

Where;

N = 10

∑XY = 499.354

∑X = 153.1

∑Y = 29.68

∑Y² = 100.546

∑X² = 2631.01

(∑ X)² = 23439.6

(∑ Y)² = 880.902

From which we have;

b = \dfrac{10 \times 499.354 -153.1 \times 29.68}{10 \times 2631.01 - 23439.6} = 0.1566

a = \dfrac{29.68 - 0.1566 \times 153.1}{10} = 0.5704

r = \dfrac{N\sum XY - \left (\sum X  \right )\left (\sum Y  \right )}{\sqrt{\left [N\sum X^{2} - \left (\sum X  \right )^{2} \right ]\times \left [N\sum Y^{2} - \left (\sum Y  \right )^{2} \right ]}}

r = \dfrac{10 \times 499.354 -153.1 \times 29.68}{\sqrt{\left (10 \times 2631.01 - 23439.6  \right )\times \left (10 \times 100.546- 880.902\right )}  } = 0.7518

r² = 0.5652  which is less than 0.7 therefore, there is a weak relationship between the variables, and it does not imply causation.

7 0
3 years ago
Help needed. Will mark brainliest. Please help:c
Alja [10]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that:

Cost of owning and operating a printer :

Purchase Cost = $100

Printing per per page = $0.05

Thus, owning and operating cost :

Purchase cost + (Printing per page * number of pages)

Number of pages = p

100 + 0.05p

Service cost :

Amount per page = 0.25

Total revenue = cost per page * number of pages

Total revenue from service =. 0.25p

The equation :

100 + 0.05p = 0.25p ; is the owning and operating cost = total revenue

It gives the equation to calculate the number of pages at which total revenue equals owning and operating cost.

100 + 0.05p = 0.25p

100 =0.25p - 0.05p

100 = 0.20p

p = 100/0.2

p = 500

When number of pages equals 500; the owning and operating cost is equal to the revenue made.

7 0
3 years ago
Simplify the radical expression (8+sqrt 11)(8-sqrt 11)
Elina [12.6K]
Foil, and should get 64-11 which equals 53.
3 0
3 years ago
Help me on this one plzz
Leona [35]

Answer:

20%

Step-by-step explanation:

pls give me brainliest

4 0
3 years ago
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