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babunello [35]
2 years ago
12

Heyy press this question! i need help, this not the last question, i have like 4 mores sooo...

Mathematics
2 answers:
UkoKoshka [18]2 years ago
8 0

Answer:

54619.875 or 55,000

Step-by-step explanation:

5020 times 9.9 is 49698

1575 times 3.125 is 4921.875

49698 plus 4921.875 is 54619.875

Marysya12 [62]2 years ago
6 0

Answer:

A. 50,00 pounds

Step-by-step explanation:

4,921.875+49,698=54,619.875 Round down to 50,000.00

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I need halp... QUESTION: tell weather the two figures are congruent. Explain your reasoning
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number 3 is not congruent but number 4 is because #4 is basically the same thing but you cant really multiply something to question #3 to get those answers.

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12/20 in simplest form
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The GCF (greatest common factor) of both of these numbers is 4, so if you divide the numerator and denominator by 4, you get 3/5.
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Mrs. Nelson has a rectangular flower box that is 5 feet long and 2 feet tall she wants the width of the box to be no more than 5
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2 years ago
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Consider the arithmetic sequence:
prisoha [69]

Answer:

<em>Answer: D</em>

Step-by-step explanation:

<u>Arithmetic Sequences </u>

The arithmetic sequences are those where any term n is obtained by adding or subtracting a fixed number to the previous term. That number is called the common difference.

The equation to calculate the nth term of an arithmetic sequence is:

a_n=a_1+(n-1)r

Where

an = nth term

a1 = first term

r   = common difference

n  = number of the term

We are given the arithmetic sequence:

10, 12, 14, 16, ...

Where a1=10 and

r = 12 - 10 = 2

Thus the general term is:

a_n=10+(n-1)2

Operating:

a_n=10+2n-2

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Answer: D

4 0
3 years ago
Read 2 more answers
A quality control specialist at a pencil manufacturer pulls a random sample of 45 pencils from the assembly line. The pencils ha
amm1812

Answer:

The P-value you would use to test the claim that the population mean of  pencils produced in that factory have a mean length equal to 18.0 cm is 0.00736.

Step-by-step explanation:

We are given that a quality control specialist at a pencil manufacturer pulls a random sample of 45 pencils from the assembly line.

The pencils have a mean length of  17.9 cm. Given that the population standard deviation is 0.25 cm.

Let \mu = <u><em>population mean length of  pencils produced in that factory.</em></u>

So, Null Hypothesis, H_0 : \mu = 18.0 cm     {means that the population mean of  pencils produced in that factory have a mean length equal to 18.0 cm}

Alternate Hypothesis, H_A : \mu\neq 18.0 cm     {means that the population mean of  pencils produced in that factory have a mean length different from 18.0 cm}

The test statistics that will be used here is <u>One-sample z-test</u> statistics because we know about the population standard deviation;

                           T.S.  =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean length of pencils = 17.9 cm

           \sigma = population standard deviation = 0.25 cm

           n = sample of pencils = 45

So, <u><em>the test statistics</em></u> =  \frac{17.9-18.0}{\frac{0.25}{\sqrt{45} } }  

                                    =  -2.68

The value of z-test statistics is -2.68.

<u>Now, the P-value of the test statistics is given by;</u>

         P-value = P(Z < -2.68) = 1 - P(Z \leq 2.68)

                      = 1- 0.99632 = 0.00368

For the two-tailed test, the P-value is calculated as = 2 \times 0.00368 = 0.00736.

7 0
3 years ago
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