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diamong [38]
3 years ago
7

What rotation is shown below?

Mathematics
2 answers:
JulijaS [17]3 years ago
5 0

Answer:

90 around the origin

Step-by-step explanation:

Here is the answer

crimeas [40]3 years ago
3 0
It’s either -90 or 90 I’m pretty sure it’s just 90
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Which pair of angles are corresponding angles
Arte-miy333 [17]
Answer is C
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3 years ago
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Does the expression 1.016x represent a percent increase greater than 12% if the original amount is x? How could I rewrite the ex
GrogVix [38]

Answer:

The expression 1.016x does not represent a percent increase greater than 12%.

Step-by-step explanation:

We are asked to find whether the expression 1.016x represent a percent increase greater than 12% if the original amount is x.

First of all, we will find 12% increase. The total amount after x% increase would be original amount plus 12% of original amount.

\text{12 percent increase}=x+\frac{12}{100}x

\text{12 percent increase}=x+0.12x    

\text{12 percent increase}=1.12x

Since 1.12 is greater than 1.016, therefore, the expression 1.016x does not represent a percent increase greater than 12%.

We can rewrite 1.016x as:

1.016x=1x+0.016x=x+0.016x

Let us convert 0.016 to percent by multiplying by 100.

0.016\times 100\%=1.6\%

Since 1.6% is less than 12%, therefore, the expression 1.016x does not represent a percent increase greater than 12%.

4 0
3 years ago
Does anybody know the answer to those two questions
Anna11 [10]

Answer:

Question Number 2 is 20

Question number 3 is 18x-32

Step-by-step explanation:

7 0
3 years ago
Find the volume of the solid obtained by rotating the region bounded by y=4x and y=2sqrt(x) about the line x=6.
Pie

Check the picture below.

so by graphing those two, we get that little section in gray as you see there, now, x = 6  is a vertical line, so we'll have to put the equations in y-terms and this is a washer, so we'll use the washer method.

y=4x\implies \cfrac{y}{4}=x\qquad \qquad y=2\sqrt{x}\implies \cfrac{y^2}{4}=x~\hfill \begin{cases} \cfrac{y}{4}=x\\\\ \cfrac{y^2}{4}=x \end{cases}

the way I get the radii is by using the "area under the curve" way, namely, I use it to get R² once and again to get r² and using each time the axis of rotation as one of my functions, in this case the axis of rotation will be f(x), and to get R² will use the "farthest from the axis of rotation" radius, and for r² the "closest to the axis of rotation".

\stackrel{R}{\stackrel{f(x)}{6}-\stackrel{g(x)}{\cfrac{y^2}{4}}}\qquad \qquad \stackrel{r}{\stackrel{f(x)}{6}-\stackrel{g(x)}{\cfrac{y}{4}}}~\hfill \stackrel{R^2}{\left( 6-\cfrac{y^2}{4} \right)^2}-\stackrel{r^2}{\left( 6-\cfrac{y}{4} \right)^2} \\\\\\ \stackrel{\textit{doing a binomial expansion and simplification}}{3y-3y^2-\cfrac{y^2}{16}+\cfrac{y^4}{16}}

now, both lines if do an equation on where they meet or where one equals the other, we'd get the values for y = 0 and y = 1, not surprisingly in the picture.

\displaystyle\pi \int_0^1\left( 3y-3y^2-\cfrac{y^2}{16}+\cfrac{y^4}{16} \right)dy\implies \pi \left( \left. \cfrac{3y^2}{2} \right]_0^1-\left. y^3\cfrac{}{} \right]_0^1-\left. \cfrac{y^3}{48}\right]_0^1+\left. \cfrac{y^5}{80} \right]_0^1 \right) \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{59\pi }{120}~\hfill

7 0
2 years ago
Please answer the following for 50 points, if you get it right you can get brainly, Please hurry!
elena55 [62]

Answer:

3.2 and 3.92

Step-by-step explanation:

4 0
2 years ago
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