Coordinates of the center: ( 4, 4 )
The radius: r = 7 - 4 = 3
The equation of a circle:
( x - 4 )² + ( y - 4 )² = 3²
x² - 8 x + 16 + y² - 8 y + 16 = 9
x² + y² - 8 x - 8 y + 32 - 9 = 0
Answer:
A ) x² + y² - 8 x - 8 y + 23 = 0
Answer:
I think its distributive
Step-by-step explanation:
I'm not sure correct me if I'm wrong
Answer:
x=17/5
Step-by-step explanation:
2 1/5=11/5
5 3/5=28/5
------------------
x+11/5=28/5
x=28/5-11/5
x=17/5
These are 2 questions and 2 answers:
<span>1.
Question 1: The area of a rectangular carpet is given by the trinomial 5x^2 - 3x -
14. What are the possible dimensions of the carpet? Use factoring.
Answer: 5x^2 -3x -14
Explanation:
You might probe the different pairs of factors given in the answer choices to check wich product is equal to the oirginal polynomial or you can factor from zero.
I will show you how to factor that polynomial from zero:
1) given: 5x^2 - 3x - 14
2) multiply and divide by the leading coefficient =>
5 [5x^2 - 3x -14 ]
----------------------
5
3) Enter the the factor 5 inside the parenthesis:
5.5x^2 - 5.3x - 5.14
--------------------------
5
4) rearrange conviniently to show (5x) as a common factir of the first two terms
(5x)^2 - 3(5x) - 70
--------------------------
5
5) factor the numerator using 5x as common term of the two binomials:
(5x ) ( 5x ) <----> open the parenthesis
(5x - ) (5x + ) <-----> include the signs
(5x - 10) (5x + 7) <---> two numbers that add up - 3 and their product is - 70
=>
(5x - 10)(5x + 7)
---------------------
5
6) divide (5x - 10) by 5 => x - 2
7) factored expression
(x - 2) (5x + 7)
8) Conclusion: the answer is the option B. (5x + 7) and (x - 2)
2. Question 2. The area of a rectangular barnyard is given by the trinomial 6x^2 +
7x – 20. What are the possible dimensions of the barnyard? Use factoring
Answer: </span><span><span>option C. (2x + 5)(3x - 4)</span>
Explanation:
The procedure is the same of the question 1.
1) given: 6x^2 + 7x - 20
2) multiply numerator and denominator by 6 and rearrange to show (6x) as common factor ot the first two terms =>
(6x)^2 + 7(6x) - 120
--------------------------
6
3) factor the numerador using 6x as common factor ot two binomials, and simplify:
(6x + )(6x - )
(6x + )(6x - )
(6x + 15) (6x - 8)
=>
(6x + 15)(6x -8)
---------------------
6
(6x + 15)(6x - 8)
---------------------- =
3.2
(6x + 15) (6x - 8)
------------- . ------------ =
3 2
(2x + 5)(3x - 4)
4) answer: option C. (2x + 5)(3x - 4)</span>
