the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
Answer: Choice A, -1540 feet
----------------------------------
Explanation:
Multiply the rate (44 ft per sec) by the number of seconds (35) to get 44*35 = 1540
The answer will be negative to indicate that the altitude has gone down. If you put in a positive change, then the altitude would go up. So that's why the answer is choice A
Note: when you multiply 44 ft/sec by 35 sec, the "second" units cancel out leaving just feet.
Another note: if you want, think of the 44 as -44 to indicate that the plane is decreasing at a rate of 44 ft/sec
All you have to do is to reverse the order of the x and y components of (7,2):
(2,7).
Answer:
The third option (9+
--
)
Step-by-step explanation:
With FOIL, this can be expanded. (a+b)(a-b) is equal to a²+ab-ab-b² or a²-b².
In this case, all the answers have 4 terms, so we want the first option. This makes the equation 3²+(3×
)-(3×)-()².
Solving these gives 9+--7. This is the same as 9+--.
**This content involves multiplying with surds and expanding perfect squares, which you may wish to revise. I'm always happy to help!
Answer:
Try c am sure it is correct
