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Kobotan [32]
3 years ago
15

The ratio for a fruit punch bowl is 7 sliced oranges to 3 limes. If James wants to make 8 fruit punch bowls, what would be the r

atio of ornages to limes?
Mathematics
1 answer:
daser333 [38]3 years ago
3 0

Answer:

i don't know

Step-by-step explanation:

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4200 the answer is d. kilo is 1000

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Translate the sentence into an equation.
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3w+7=9

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If The Area Of Triangle MNO Is 24cm2 Find The Area Of Triangle PNO​
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24 cm^2

Step-by-step explanation:

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8 0
2 years ago
The graph of a proportional relationship contains the point (8, 4).
Softa [21]
\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\
(\stackrel{x}{8}~~,~~\stackrel{y}{4})\implies 
\begin{cases}
x=8\\
y=4
\end{cases}\implies 4=k8\implies \cfrac{4}{8}=k\implies \cfrac{1}{2}=k
\\\\\\
\boxed{y=\cfrac{1}{2}x}
6 0
4 years ago
All bags entering a research facility are screened. The screening process is not perfect so that 77% of the bags that contain fo
garik1379 [7]

Answer:

(1) 0.5933

(2) 0.8955

Step-by-step explanation:

We are given that all bags entering a research facility are screened.

Let Probability that bags entering the building contains forbidden material,

 P(F) = 0.69

Probability that bags entering the building does not contains forbidden material,   P(NF) = 1 - 0.69 = 0.31

Let event A = alarm gets triggered

Probability that alarm gets trigger given the bags contain forbidden material, P(A/F) = 0.77

Probability that alarm gets trigger given the bags does not contain forbidden material, P(A/NF) = 0.20

(1) Probability that a bag triggers the alarm, P(A) ;

         P(A) = P(F) * P(A/F) + P(NF) * P(A/NF)

                 = (0.69 * 0.77) + (0.31 * 0.20) = 0.5313 + 0.062

                 = 0.5933

Therefore, probability that a bag triggers the alarm is 0.5933 .

(2) Probability that a bag that triggers the alarm will actually contain forbidden material is given by P(F/A) ;

Using Bayes' Theorem;

    P(F/A) = \frac{P(F) * P(A/F)}{P(F) * P(A/F) + P(NF) *P(A/NF)} = \frac{0.69*0.77}{0.69*0.77+0.31*0.20} = \frac{0.5313}{0.5933}

               = 0.8955

6 0
4 years ago
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