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Flauer [41]
3 years ago
5

Which of the following is a correct interpretation of the expression 6 - 136−, minus, 13?

Mathematics
1 answer:
Darina [25.2K]3 years ago
6 0

Answer:

(Choice A)

A

Start at 131313 on the number line and move 666 to the left.

Step-by-step explanation:

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Number seven on the page
prohojiy [21]
Multiply 9.75 by 1.5 to get 14.63 fluid ounces.
6 0
3 years ago
Heather received $100 for her 13th birthday if she saves it in a bank with 3% interest compounded quarterly how much money will
ololo11 [35]

Answer:

109.38

Step-by-step explanation:

Recall the formula for compound interest is as follows:

         A  =  P·(1  +  r/n)nt ,   where

    P = principal amount (initial amount deposited)

     r = annual rate of interest (in decimal form)

     t = # of years amount is deposited for

    n = # of times interest is compounded per year

    A = amount accumulated after t years, including interest

The problem asks how much money Heather will have in the bank by her 16th birthday when she deposited $100 on her 13th birthday in a bank with 3% interest compounded quarterly. From this, we have the following information:

    P = $100

    r = 0.03     ==>     3%/100% = 0.03

    t = 3 years     ==>     16 - 13 = 3

    n = 4     ==>     since there are 12 months per year and 12/4 = 3 months,

                then interest is compounded  every 3 months which is a total of 4 times per year

Therefore,

         A = P(1 + r/n)nt

            = 100(1 + 0.03/4)4·3

            = 100(1 + 0.0075)12

            = 100(1.0075)12

            = 109.38069

            ≈ 109.38

Thus, Heather will have $109.38 in the bank by her 16th birthda

6 0
3 years ago
34576637 + 2373773883. l
Zigmanuir [339]

The answer to your question is: 2,408,350,520.

Give brainliest please and i hope this helps alot. :D

7 0
4 years ago
Read 2 more answers
What are the orders of 3,7,9,11,13,17 and 19(mod20)?does 20 have primitive roots?
bezimeni [28]
3\equiv3\mod{20}
3^2\equiv9\mod{20}
3^3\equiv27\equiv7\mod{20}
3^4\equiv3\cdot3^3\equiv3\cdot7\equiv21\equiv1\mod{20}

7\equiv7\mod{20}
7^2\equiv49\equiv9\mod{20}
7^3\equiv7\cdot7^2\equiv63\equiv3\mod{20}
7^4\equiv7\cdot7^3\equiv21\equiv1\mod{20}

9\equiv9\mod{20}
9^2\equiv3^4\equiv1\mod{20}

11\equiv11\mod{20}
11^2\equiv121\equiv1\mod{20}

13\equiv-7\equiv13\mod{20}
13^2\equiv169\equiv9\mod{20}
13^3\equiv13\cdot13^2\equiv(-7)9\equiv-63\equiv-3\mod{20}
13^4\equiv13\cdot13^3\equiv(-7)(-3)\equiv21\equiv1\mod{20}

17\equiv-3\equiv17\mod{20}
17^2\equiv(-3)^2\equiv9\mod{20}
17^3\equiv(-3)^3\equiv-27\equiv3\mod{20}
17^4\equiv(-3)^4\equiv81\equiv1\mod{20}

19\equiv-1\equiv19\mod{20}
19^2\equiv19(-1)\equiv-19\equiv1\mod{20}

Generally speaking, a number x coprime to n will be a primitive root of n if we have x^n\equiv x\mod{n}, or x^{n-1}\equiv1\mod{n}. In other words, if x is of order n-1 modulo n, then x is a primitive root of n.

Since none of these numbers has order 19, it follows that 20 does not have any primitive roots.
6 0
4 years ago
What is the sum of 2/10 and 9/100
zhannawk [14.2K]
First we need to find a common denominator

\frac{2}{10}=\frac{20}{100}
now we can add them

\frac{20}{100}+\frac{9}{100}=\frac{29}{100}
5 0
3 years ago
Read 2 more answers
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