<h3>Radius = 14cm</h3>
Step-by-step explanation:
Let O be the centre of the circle. Since P and S are the points of contact of tangents AD and DC respectively, OP ⊥ AD and OS ⊥ DC
Also, AD ⊥ DC (given), therefore, OPDS is a square.
BR = BQ = 27cm...(tangents from an external point to a circle are equal in length)
therefore, CR = CB - BR = (38 - 27)cm = 11cm
SC = CR = 11 cm...(tangents from an external point) therefore, DS = DC - SC = (25 - 11) cm = 14 cm.
therefore,
Radius of a circle = OP = DS = 14 cm...(therefore, OPDS is a square).
<h3>Hope it helps you!! </h3>
Answer:
Test statistic = -2.44
There is enough evidence to support the strategist's claim.
Step-by-step explanation:
H0 : p = 0.41
H1 : p < 0.41
pˆ = 0.38
Test statistic :
z=pˆ−p/√p(1−p)/n
Z = (0.38 - 0.41) / √(0.41(1 - 0.41) / 1600
Z = - 0.03 / √0.0001511875
Z = - 0.03 / 0.0122958
Z = - 2.4399
Test statistic = -2.44
The Pvalue :
P(Z < -2.44) = 0.0073436
α - level = 0.02
If Pvalue < α ; Reject H0
0.0073436 < 0.02 ; We reject H0
Since Pvalue < α ; Hence, There is enough evidence to support the strategist's claim.
Answer:
546
Step-by-step explanation:
Surface Area = 2(lw + lh + wh)
plug in 21 10.5 and 2.5
Answer: e^y=x
ln(x)=y
e^ln(x)=e^y
x=e^y
y = -13, 13
There are two answers because you are taking the square root of a number. If we go the other way, to check our work, (-13)^2 = 169 and (13)^2 = 169.
Hope this helps! :)
