Given the following triangle, determine the measure of angle B to the nearest<br> degree

One of the wagers in roulette is to bet that the ball will stop on a number that is a multiple of 3. (Both 0 and 00 are not incl

Arlecino [84]

Answer:

The players expectation is -0.1052

Step-by-step explanation:

Consider the Roulette numbers to from 1-36, also the two green zeroes 0 and 00,

Thus, there are 38 places on which the ball can land.

On first 36 numbers, 12 of them are divisible by 3. Also there are 26 numbers which are not divisible by 3.

The probability of a wager winning is: 12/38 or 6/19

Now the probability of a wager to loss is: 26/38 or 13/19

So for a 6/19 chance of winning $4 and a 13/19 chance of losing $2.

Therefore, the expected outcome is:

4 × 6/19 + -2 × 13/19 = 1.2632 - 1.3684 = -0.1052

The expected value comes up with a negative sign. Hence, he will lose money.

The players expectation is -0.1052

8 0

3 years ago

Which procedure could be used to graph the following equation ? y=1/4x - 1

aalyn [17]

Answer: A.

Step-by-step explanation:

Plot the y-intercept (0,-1) and use the slope of 1/4 to find a second point

4 0

3 years ago

Read 2 more answers

25 POINTS PLEASE HELP

Minchanka [31]

Answer:

corresponding angles

1=5

3=7

2=6

4=8

alternative exterior

2=7

1=8

alternative interior

4=5

3=6

3 0

3 years ago

Read 2 more answers

The coordinates of the endpoints of AB and CD are A(2,

Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

$m= \frac{y_2-y_1}{x_2-x_1}$

Formula to Find Distance between two points

$D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}$

mAB ( represents , Slope of AB )

1. $mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}$

2. $mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}$

3. $mCD=\frac{5-2}{6-5}=\frac{3}{1}=3$

4. $AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

5. $BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

mAC = mBC , and C is common point , hence these three are collinear points making a straight line whole slope is $-\frac{1}{3}$

$mAB=-\frac{1}{3}$

$mCD=3$

$mAB \times mCD = -\frac{1}{3} \times 3 = -1$

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0

3 years ago

What prompted (caused) Gandhi to begin a campaign of passive resistance in South Africa?

Firlakuza [10]

Answer:

Asiatic Registration Bill of 1906.

Step-by-step explanation:

The first passive resistance campaign was started in Johannesburg in 1907 with, and for, the wealthy South African Indian merchants whom he had so long represented.’ Gandhi’s first passive resistance campaign began as a protest against the Asiatic Registration Bill of 1906.

5 0

2 years ago

Given the following triangle, determine the measure of angle B to the nearest degree