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liraira [26]
3 years ago
6

Which two values are of x are roots of the polynomial below? 4x^2-6x+1

Mathematics
1 answer:
slavikrds [6]3 years ago
8 0
The roots are 1.309 and 0.19098



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Help regular 7th grade math​
Reptile [31]

Answer:

Y = <u><em>5x</em></u> + <em><u>3</u></em>

Now for the other one if your asking is:

Y = <em><u>-12x</u></em> + <em><u>4</u></em>

<em><u /></em>

Hope this helped if so please mark brainlist!

3 0
3 years ago
Factories 54m3n + 81m4n2 b) 15x2y3z + 25x3y2z + 35x2y2z​
Oliga [24]

<u>Part a)</u>

Given the expression

54m^3n\:+\:81m^4n^2

Apply exponent rule:    a^{b+c}=a^ba^c

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn     ∵ m^4n^2=m^3mnn

Rewrite 81 as 3 · 27

Rewrite 54 as 2 · 27

                             =2\cdot \:27m^3n+3\cdot \:27m^3mnn

Factor out the common term:   27m³n

                              =27m^3n\left(2+3mn\right)      

Therefore,

54m^3n\:+\:81m^4n^2=54m^3n+81m^3mnn=27m^3n\left(2+3mn\right)

<u>Part B)</u>

Given the expression

15x^2y^3z+25x^3y^2z+35x^2y^2z

Apply exponent rule:    a^{b+c}=a^ba^c

15x^2y^3z+25x^3y^2z+35x^2y^2z=15x^2y^2yz+25x^2xy^2z+35x^2y^2z

Rewrite as

                                               =3\cdot \:5y^2x^2zy+5\cdot \:5y^2x^2zx+7\cdot \:5y^2x^2z

Factor out common term 5y²x²z

                                                =5y^2x^2z\left(3y+5x+7\right)

Therefore,

15x^2y^3z+25x^3y^2z+35x^2y^2z=5y^2x^2z\left(3y+5x+7\right)

8 0
3 years ago
Simplify the expression. -2(x + 5) - x + 4
wlad13 [49]

Answer:

−3 x −6

Step-by-step explanation:

7 0
3 years ago
Show that there is no solution for the radical equation 4w+4=-4.
Ad libitum [116K]

Answer:

there is a solution

w= -2

Step-by-step explanation:

4w+4=-4

    -4    -4

4w=-8

/4    /4

w=-2

3 0
3 years ago
Use the limit theorem and the properties of limits to find the limit.<br> Picture provided below
sashaice [31]

Answer:

b. 1/2

Step-by-step explanation:

lim        (x -3)(x +2)

x-->-∞    ---------------

              2x^2 + x +1

= lim        (x^2 -3x +2x - 6)

x-->-∞    -----------------------

              2x^2 + x +1

= lim        (x^2 -x - 6)

x-->-∞    -----------------------

              2x^2 + x +1

When we plug in x = -∞, we get indeterminate form.

Now we have to use the L'hospital rule.

d/dx (x^2 - x - 6) = 2x -1

d/dx (2x^2 + x + 1) = 4x + 1

Now apply the limit

lim            (2x - 1) / (4x + 1)

x--->-∞

Here we have to degree of the numerator and the denominator of the same. In this case, if x --> -∞, we get the result as the coefficient of the leading term as the result.

According to the rule, we get

= 2/4

Which can simplified as 1/2

The answer is 1/2

Hope this will helpful.

Thank you.

3 0
3 years ago
Read 2 more answers
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