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3 years ago

I need some help x+9x

Mathematics

2 answers:

nekit [7.7K]3 years ago

7 0

The answer your looking for is 10x

Lera25 [3.4K]3 years ago

3 0

10x is the answer!! i hope its righy

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A batch of snack mix made of dried fruit and nuts contain 744G of nuts the ratio of nuts to dried fruit by weight is 12 to 13 ho

mixer [17]

In a bag of snack mix:

n = nuts d = dried fruit

n = 744g d = ???g

Ratio Nuts/Dried fruit = 12/13

This basically means that if the mix was divided in 25 parts, 12 parts would be nuts and 13 would be dried fruits

If 744 is 12 parts then 744/12 is 1 part

744/12 = 62

1 part = 62g

there are 13 parts of dried fruit

13 x 62 = 806

744g of nuts + 806g of dreid fruit = 1550g

Answer: A batch of snack mix weigh 1550g, or 1.55kg

hope it helps :)

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3 years ago

This statement accurately describes how to determine the Y intercept and the slope from the graph below

Artist 52 [7]

Answer:

i dont see nun

Step-by-step explanation:

please explain

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2 years ago

Can someone answer this plz im giving brainliest

kotegsom [21]

Answer:

1, 3, 5, 7, 10 those are the answers to Y

7 0

3 years ago

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Calculate: a+x 2 − a−x 2 , if a=−2; x=−6

babunello [35]

0, because ur doing a-a and 2x-2x which equals nothing

8 0

3 years ago

As part of quality-control program, 3 light bulbs from each bath of 100 are tested. In how many ways can this test batch be chos

hichkok12 [17]

Answer:

<h3>By 161700 ways this test batch can be chosen.</h3>

Step-by-step explanation:

We are given that total number of bulbs are = 100.

Number of bulbs are tested = 3.

Please note, when order it not important, we apply combination.

Choosing 3 bulbs out of 100 don't need any specific order.

Therefore, applying combination formula for choosing 3 bulbs out of 100 bulbs.

$^nCr = \frac{n!}{(n-r)!r!}$ read as r out of n.

Plugging n=100 and r=3 in above formula, we get

$^100C3 = \frac{100!}{(100-3)!3!}$

Expanding 100! upto 97!, we get

= $\frac{100\times 99\times 98\times 97!}{97!3!}$

Crossing out common 97! from top and bottom, we get

= $\frac{100\times 99\times 98}{3!}$

Expanding 3!, we get

= $\frac{100\times 99\times 98}{3\times 2\times 1}$

= 100 × 33 × 49

= 161700 ways.

<h3>Therefore, by 161700 ways this test batch can be chosen.</h3>

3 0

3 years ago