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Semenov [28]
3 years ago
13

15 POINTS!!!!!

Mathematics
2 answers:
dusya [7]3 years ago
7 0
A. SAS Hope this help
Viefleur [7K]3 years ago
4 0

Answer:

A. SAS

the triangle is congruent by side angle and side

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Please help! I really need help...
Sholpan [36]

Answer:

3y^{2}+2y-11

Step-by-step explanation:

we have

(-y^{2}-4y-8)-(-4y^{2}-6y+3)

Eliminate the parenthesis

-y^{2}-4y-8+4y^{2}+6y-3

Group terms that contain the same variable

-y^{2}+4y^{2}-4y+6y-8-3

Combine like terms

3y^{2}+2y-11

4 0
3 years ago
What is the solution of the system of equations?
Zolol [24]
X=2, y=4
Hope this helps :)
<br>
I used the Elimination Method
3 0
4 years ago
Read 2 more answers
1. The hypotenuse of a right triangle measures 2 sqrt 15 centimeters and its shorter leg measures 2 sqrt 6
Dominik [7]

Answer:

<h2>50.8°</h2>

Step-by-step explanation:

First, we need to use the Pythagorean Theorem to find the third side. We will then use the law of cosines to find the angle.

2√15² = 2√6² + b²

60 = 24 + b²

Subtract 24

36 = b²

b = 6

Now, that we have all three sides, we will use the law of cosines to figure out the angle.

c² = a² + b² - 2abCosC°

Substitute the values in.

6² = 2√15² + 2√6² - 2(2√15)(2√6)CosC°

36 = 60 + 24 - 2(37.947331922)CosC°

36 = 60 + 24 - 75.894663844CosC°

36 = 84 - 75.894663844CosC°

Subtract 84

-48 = -75.9CosC°

0.63241106719 = CosC°

Arccos (0.63241106719) = 50.77176844°

The largest acute angle is approximately 50.8°

8 0
3 years ago
Read 2 more answers
Give the slope and the y-intercept of the line y = − 8 x + 10 . Make sure the y-intercept is written as an ordered pair.
nadezda [96]
Y=mx+b is slope-intercept form. M is the slope so the slope would be -8. B in the y-intercept which is 10. The y-intercept is where your line crosses the y-axis, so the x-coordinate is 0. The ordered pair is (0, 10).
7 0
3 years ago
BRAINLIEST AVAILABLE!!!!<br><br> PLEASE HELP ME WITH THIS!!!<br> Thanks to all helpers!!!!!
larisa [96]

Answer: B

<u>Step-by-step explanation:</u>

-10x² + 12x - 9 = 0

a=-10, b=12, c=-9

x = \frac{-b+/-\sqrt{b^{2}-4ac}} {2a}

  = \frac{-12+/-\sqrt{12^{2}-4(-10)(-9)}} {2(-10)}

  = \frac{-12+/-\sqrt{144-360}} {-20}

  = \frac{-12+/-\sqrt{-216}} {-20}

  = \frac{-12} {-20} +/- \frac{\sqrt{-216}} {-20}

  = \frac{3} {5} +/- \frac{6i\sqrt{6}} {-20}

  = \frac{3} {5} +/- \frac{3i\sqrt{6}} {10}

3 0
4 years ago
Read 2 more answers
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