The number 123 is a composite number. The factors of 123 are: 1, 3, 41, and 123. This means each of those numbers can divide 123 evenly.
Answer:
5 1/8
Step-by-step explanation:
41÷8 is 5 remainder 1, since 40÷5=8
Since 5 wholes fit in we put this before the fraction and whatever the remainder is we put as the numerator.
Therefore our answer is :
5 1/8
Answer: A △ABC such that the bisectors of ∠ABC and ∠ACB meet at a point O.
To prove :
∠BOC=90
o
+
2
1
∠A
Step-by-step explanation: In △BOC,
∠1+∠2+∠BOC=180
o
In △ABC,
∠A+∠B+∠C=180
o
∠A+2(∠1)+2(∠2)=180
o
2
∠A
+∠1+∠2=90
o
∠1+∠2=90
o
−
2
∠A
Answer:
x = - 3, x = - 2
Step-by-step explanation:
Given
x² + 5x + 6 = 0
Consider the factors of the constant term (+ 6) which sum to give the coefficient of the x- term (+ 5)
The factors are + 3 and + 2, since
3 × 2 = + 6 and 3 + 2 = + 5, thus
(x + 3)(x + 2) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 3 = 0 ⇒ x = - 3
x + 2 = 0 ⇒ x = - 2
