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marysya [2.9K]
3 years ago
11

Someone please help

Mathematics
1 answer:
VladimirAG [237]3 years ago
6 0
The top answer is correct.
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Is this an example of a horizontal asymptote?
8_murik_8 [283]

Answer:

Step-by-step explanation:

Hi there,

The graph indicated is showing a horizontal asymptote. In fact, it is showing both a horizontal and a <em>vertical </em>asymptote.

To tell which type it is, notice where the graph "shoots off" and almost forms an imaginary straight line in one direction. Using this logic, the horizontal asymptote will be exactly horizontal, parallel to x-axis, and vertical asymptote will be exactly vertical, parallel to y-axis.

With this graph, we notice the horizontal asymptote is at y=0, where the x-axis is. The vertical asymptote is bit more difficult to determine graphically, but can definitely say it is past x=-10. We could determine it if we had the function, but that is not necessary for this question.

Study well, and persevere. If you liked this solution, leave a Thanks or give a rating!

thanks,

6 0
3 years ago
How many minutes are there in 4 and a half hours?
Annette [7]
1 \ hour=60 \ minutes \\\\ a \ half \ an \ hour = \frac{1 \ hour}{2}=\frac{60min}{2}=30 minutes \\\\ 4 \ hurs \ and \ a half = 4*60+30= \\\\ =240+30=\\\\ =\boxed{270}
7 0
3 years ago
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29300$ at 10% for six years use simple interest to find the ending balance show all work
krok68 [10]

Answer:

17580

Step-by-step explanation:

29300*0.10*6=I

29300*0.6=I

17580=Interest

5 0
2 years ago
Find the surface area of each rectangular prism 4 in by 5 in by 12in
8090 [49]
2(20+60+48)=2(128)= 256 square inches

Hope it helps
8 0
3 years ago
Can yall help meee please
alexira [117]

Answer:

jupiters \: mass \: is \: approximatelty \:  \\   \boxed{{6 \times 10}^{3} \: kg}  \: times, \:  \\ more \: than \: mercurys \: mass

Step-by-step explanation:

............................................................... \\ in \: other \: to \: get \: right \: ans \to \\ you \: divide \: mass \: of \: jupiter \: by \: the \: mass \\  \: of \: mercury : \: so \to \\ ............................................................... \\ jupiters \: mass = 1.898 { \times 10}^{27}  \: kg \\ mercurys \: mass =3.3 \times  {10}^{23}   \: kg \\ their \: mass \: ratio \: is :  \\  =  \frac{1.898 { \times 10}^{27}}{3.3 \times  {10}^{23}}  = 0.5751515152 \times  {10}^{4}   =  \\  \boxed{5,751.515152} \\ hence \: jupiters \: mass \: is \: approximatelty \:  \\  {6 \times 10}^{3}  \: times \: more \: than \: mercurys \: mass

5 0
3 years ago
Read 2 more answers
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