Someone please help

Use the figure below for Exercises 1-8. Note that RN pierces the plane at N. It is not coplanar with V.

Serga [27]

Answer:

1. Two segments are MC and AX

2. Point N

3. Three collinear points are points A, point N and point X

4. Two other names for V are quadrilateral and rectangle

5. No N, M, and X are in a different plane from R

6. Two rays are ray NR and ray NA

7. The pair of opposite rays with end point N are ray NA and ray NX and ray NM and ray NC

8. Three lines are shown in the figure

Step-by-step explanation:

1) A segment is a line portion with two end points

2) A point marks a position

3) Collinear points are points on the same line

3) A quadrilateral is a four sided figure while rectangle has 90° interior angles

4) A ray is an line extending from a point without ending

5) Opposite rays are rays extending from the same point but in opposite directions

6) A line is a straight one dimensional geometric figure that has no width but infinite number of points extending without end in both directions

4 0

2 years ago

Using the order of operations, what should be done first to evaluate 6 squared + 10 divided by (negative 5) (3) minus 5?

tiny-mole [99]

If anything is in parentheses do that first, however if there isn’t you always do exponents next so evaluate 6 squared
Hope this helps!!

3 0

3 years ago

Read 2 more answers

Find the circumference of the circle to the nearest tenth.

Y_Kistochka [10]

C = 2(PI)r multiply 2 x 3.14 x (whatever the radius is!

7 0

3 years ago

Write an equation that represents the line. (-3,-6) and (2,-2) use exact numbers

Ilia_Sergeevich [38]

Given:

The line passes through (-3,-6) and (2,-2).

To find:

The equation of line.

Solution:

If a line passes through two points $(x_1,y_1)\text{ and }(x_2,y_2)$ , then the equation of line is

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

The line passes through (-3,-6) and (2,-2). So, the equation of line is

$y-(-6)=\dfrac{-2-(-6)}{2-(-3)}(x-(-3))$

$y+6=\dfrac{-2+6}{2+3}(x+3)$

$y+6=\dfrac{4}{5}(x+3)$

$y+6=\dfrac{4}{5}(x)+\dfrac{4}{5}(3)$

Subtract 6 from both sides.

$y=\dfrac{4}{5}(x)+\dfrac{12}{5}-6$

$y=\dfrac{4}{5}(x)+\dfrac{12-30}{5}$

$y=\dfrac{4}{5}(x)+\dfrac{-18}{5}$

$y=\dfrac{4}{5}(x)-\dfrac{18}{5}$

Therefore, the equation of line is $y=\dfrac{4}{5}(x)-\dfrac{18}{5}$ .

3 0

3 years ago

Solve the compound inequality 4x – 7 > 5 or 5x + 4 ≤ –6

bija089 [108]

Answer:

inequality form: x $\leq$ -2 or x > 3

interval notation form: (-∞,-2] ∪ (3,∞)

Step-by-step explanation:

I attached a picture that shows all the work. You begin by isolating then solving for x on both sides. Then form a solution using the information found out about x. For example, you can combine the found inequalities for x to solve that x must be GREATER than 3 while being LESS than -2. Using that you can form an line and make a line. Remember, when writing in interval notation form you always begin from the left to the right (in reference) to the number line.

5 0

2 years ago