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3 years ago

Hiii dont mind the answer that i put but im not sure if im right, can someone please help me?

Mathematics

1 answer:

AVprozaik [17]3 years ago

3 0

Answer:

Option 4

Step-by-step explanation:

The volume of a cylinder is going to be the area of the base (which is a circle) times the height. if you have cylindrical mug, then you can use the base area×height relationship, but it won't be exact because some of the volume is going to be used for the walls of the mug itself.

Anyways:

Volume = Base Area × Height

•Base Area -> Circle = π×radius²

•Height is given as 7in.

Volume = π×(6.2in)² × 7in = 845.33975...

Volume is in units cubed (the 3rd power) which is where the in³ is from. Your closest option here looks to be the 4th choice.

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2 years ago

The square abcd has side length 10cm. E is the midpoint of BC. Work out the length of DE. Answer to 1 decimal place.

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-- DEC is a right triangle.

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2 years ago

Read 2 more answers

When the sum of 5 and three times a positive number is subtracted from the square of the number, 0 results. Find the number.

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$x-the\ number\\\\x^2-(5+3x)=0\\\\x^2-5-3x=0\\\\x^2-3x-5=0$

$Use\ the\ quadratic\ formula:\\a^2x+bx+c=0\\\\\Delta=b^2-4ac\\\\if\ \Delta > 0\ then\ x_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ x_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\if\ \Delta=0\ then\ x_0=\dfrac{-b}{2a}\\\\if\ \Delta < 0\ then\ no\ solution$

$x^2-3x-5=0\\\\a=1;\ b=-3;\ c=-5\\\\\Delta=(-3)^2-4\cdot1\cdot(-5)+3+20=29 \ \textgreater \ 0\\\\\sqrt\Delta=\sqrt{29}\\\\x_1=\dfrac{3-\sqrt{29}}{2\cdot1}=\dfrac{3-\sqrt{29}}{2} \ \textless \ 0\\\\x_2=\dfrac{3+\sqrt{29}}{2\cdot1}=\dfrac{3+\sqrt{29}}{2} \ \textgreater \ 0$

$Answer:\ \boxed{x=\dfrac{3+\sqrt{29}}{2}}$

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