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disa [49]
2 years ago
6

You Stupid whats 9+10

Mathematics
2 answers:
devlian [24]2 years ago
7 0

Answer: 19 booooooooooiii


Ilia_Sergeevich [38]2 years ago
4 0

Answer:

910 duh omegalul

Step-by-step explanation:


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The function g(x) = p sin x +q, where p>0, has a maximum value of 10 and a minimum value of -4. Find the value of p and of q.
tester [92]

Answer: p=7, q=3

Step-by-step explanation:

The midline of the function is

\frac{10-4}{2}=3 \implies q=3

This means that to obtain a maximum of 10, when \sin x reaches it's maximum, 1, g(x)=p+q=10 \implies p=7

7 0
2 years ago
What is the solution of log2 (3x-7) =3
Valentin [98]

Answer:

x = 5

Step-by-step explanation:

because the log is base 2 you can remove the log by raing 2 to the power of each side:

2^{log2 (3x-7)} = 2^{3}

the 2 and log2 cancel leaving:

3x-7 = 2^{3}

this means we can now solve through simple algebra:

3x-7 = 8\\3x = 8 + 7\\3x = 15\\3x/3 =15/3\\x = 5

7 0
3 years ago
Read 2 more answers
jessie worked four more hours than Ben. They worked a total of 25 hours. How many hours did each boy workz?
Mandarinka [93]

Answer:

jessie: 14.5

ben: 10.5

3 0
3 years ago
When the same whole number is added to both the numerator and denominator of $\frac{2}{5}$, the value of the new fraction is $\f
AVprozaik [17]

Answer:

Correct answer: x = 4

Step-by-step explanation:

If I saw your fractions right it's like this:

(2 + x) / (5 + x) = 2 / 3 => 3 (2 + x) = 2 (5 + x) => 6 + 3 x = 10 + 2 x

3 x - 2 x = 10 - 6  => x = 4

We will check

2 + 4 / 5+ 4 = 6 / 9  

When we divide both numerator and denominator

with 3 we get 2/3

God is with you!!!

3 0
3 years ago
Need Help! I don't get it
serious [3.7K]
Well hmmm let's say you take the car and go in the city for 60 miles with it, well, the car can do 60 miles per gallon, since you just drove it for 60 miles, you only spent 1 gallon of gasoline then.

that only happens if you drive it for 60 miles, what if you drive it for more, let's do a quick table on that,

\bf \begin{array}{ccll}
miles&cost\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
60&3.6(1)\\\\
&3.6\left( \frac{60}{60} \right)\\\\
120&3.6(2)\\\\
&3.6\left( \frac{120}{60} \right)\\\\
180&3.6(3)\\\\
&3.6\left( \frac{180}{60} \right)
\end{array}

and so on, now let's check if you less than 60 miles,

\bf \begin{array}{ccll}
miles&cost\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
40&3.6\left( \frac{40}{60} \right)\\\\
20&3.6\left( \frac{20}{60} \right)\\\\
10&3.6\left( \frac{10}{60} \right)
\end{array}

so, if you divide the amount of miles driven, by 60, when you have driven it for 120 miles, 120/60 is just 2, and the cost is for 2 gallons, or 3.6 * 2, which is 7.2 bucks, for 180 miles is 180/60 or 3 gallons for 3.6 * 3 bucks, and so on.

now, what if you drive it instead for "m" miles?

\bf \begin{array}{ccll}
miles&cost\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
m&3.6\left( \frac{m}{60} \right)\\\\
\end{array}\implies c=3.6\left( \cfrac{m}{60} \right)\implies c=\cfrac{3.6m}{60}
\\\\\\
c=\cfrac{3.6}{60}m\implies c=0.06m
3 0
3 years ago
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