They need to walk 2 dogs for the box of treats
Answer:
-0.16666 and 6 repeats
Step-by-step explanation:
Answer:
t=11,11 days
Step-by-step explanation:
F=frogs poblation, t=time, be the variables dF/dt = KF, dF/F=Kdt, integrating 
⇒ LnF=Kt+c,
; Knowing t=0, F=17 and t=6 F=51 (tripling every 6 days (17*3)), 
⇒
, so 
, now if F=130, t=? we have:
h(x) = 3 * (2)^x
Section A is from x = 1 to x = 2
h(1) = 3 * (2)^1 = 3 * 2 = 6
h(2) = 3 * (2)^2 = 3 * 4 = 12
so
the average rate of change = (12 - 6)/(2 - 1) = 6
Section B is from x = 3 to x = 4
h(3) = 3 * (2)^3 = 3 * 8 = 24
h(4) = 3 * (2)^4 = 3 * 16 = 48
so
the average rate of change = (48 - 24)/(4 - 3) = 24
Part B: How many times greater is the average rate of change of Section B than Section A? Explain why one rate of change is greater than the other. (6 points)
the average rate of change of section B is 24 and the average rate of change of section A is 6
So 24/6 = 4
The average rate of change of Section B is 4 times greater than the average rate of change of Section A
It's exponential function, not a linear function; so the rate of change is increasing.
So firstly, I'm going to be converting the mixed number into an improper fraction. To do this, multiply the whole number by the denominator and then add that product with the numerator and that will be your new numerator. In this case:
3 × 8 = 24, 24 + 3 = 27. 
Now since they have the same denominator, you can subtract the numerators.
Now simplify the number as such:
<u>In short, your answer is -17/4, or -4 1/4.</u>
